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Old 18th November 2011, 10:47 AM   #1
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Default Output transformer question

I have a small amp using the 6c45pi. The output transformer has 4 and 8 ohm taps but I am considering hooking a 32 ohm speaker to it. Assuming
I am getting 1w into 8 ohms what should my output be into 32 ohms.
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Old 18th November 2011, 09:16 PM   #2
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1w into 8 ohms needs 2.8volts. 2.8 v into 32 ohms gives 1/4 watt.
Power = volts x amps
Power = volts squared divided by resistance
Power = amps squared times resistance
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Old 19th November 2011, 12:57 AM   #3
Gilgy is offline Gilgy  United Kingdom
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Quote:
Originally Posted by woody View Post
The output transformer has 4 and 8 ohm taps but I am considering hooking a 32 ohm speaker to it
Why?
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Old 19th November 2011, 02:20 AM   #4
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Quote:
Originally Posted by payitforwardeddie View Post
1w into 8 ohms needs 2.8volts. 2.8 v into 32 ohms gives 1/4 watt.
Power = volts x amps
Power = volts squared divided by resistance
Power = amps squared times resistance
disregarding the shift in the operating point of the output tube due to the change in the reflected impedance...
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Old 19th November 2011, 01:10 PM   #5
DF96 is offline DF96  England
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Yes, it all depends on the output impedance (which is the triode anode impedance transformed by the transformer). Without knowing this you can't do an exact calculation. However, some reduction in output power is likely.
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