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#1 |
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diyAudio Member
Join Date: Aug 2010
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Radiotron says the voltage gain of a power amplifier is 2.82*sqrt(Po*RL). Is this equation used all the time for power amp design, including push-pull?
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#2 |
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diyAudio Member
Join Date: Aug 2009
Location: Johnson City, TN
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Which RDH? 4?
Which chapter, page, etc... |
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#3 |
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diyAudio Member
Join Date: Aug 2010
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#4 |
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diyAudio Member
Join Date: May 2007
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sqrt(Po*RL) is a voltage, not a gain. The 2.82 factor makes it a peak-peak voltage for a sine wave signal.
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#5 |
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diyAudio Member
Join Date: Aug 2010
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#6 |
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diyAudio Member
Join Date: Aug 2009
Location: Johnson City, TN
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This is the voltage gain of a triode output stage.
As DF96 pointed out, 2.82 is the factor from peak to RMS. The equation you gave is half the necessary information. It relates voltage gain M to power our when known along with the load resistance. The second formulae : M=(Emax-Emin)/2Ec1 defines the voltage gain as the ratio of the maximum output voltage divided by twice the input bias voltage on the grid, assuming an idealized condition where there is no grid current flowing at Vgk=0. From 1 & 2 you can equate output power to voltage gain if you know the load resistance by stating: 2.82 SQRT(PoRl)= M =(Emax-Emin)/2Ec1 Rearanging you get Po=((Emax-Emin)/2Ec1*2.82)^2)/Rl |
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