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Old 10th October 2011, 07:01 PM   #1
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Default Radiotron question

Radiotron says the voltage gain of a power amplifier is 2.82*sqrt(Po*RL). Is this equation used all the time for power amp design, including push-pull?
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Old 10th October 2011, 07:37 PM   #2
TheGimp is online now TheGimp  United States
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Which RDH? 4?

Which chapter, page, etc...
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Old 10th October 2011, 07:44 PM   #3
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Which RDH? 4?

Which chapter, page, etc...
RDH 4, chapter 13, page 549.
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Old 10th October 2011, 07:47 PM   #4
DF96 is offline DF96  England
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sqrt(Po*RL) is a voltage, not a gain. The 2.82 factor makes it a peak-peak voltage for a sine wave signal.
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Old 10th October 2011, 07:51 PM   #5
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Originally Posted by TheGimp View Post
Which RDH? 4?

Which chapter, page, etc...
RDH 4, chapter 13, page 549.
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Old 10th October 2011, 08:06 PM   #6
TheGimp is online now TheGimp  United States
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This is the voltage gain of a triode output stage.

As DF96 pointed out, 2.82 is the factor from peak to RMS.

The equation you gave is half the necessary information. It relates voltage gain M to power our when known along with the load resistance.

The second formulae : M=(Emax-Emin)/2Ec1
defines the voltage gain as the ratio of the maximum output voltage divided by twice the input bias voltage on the grid, assuming an idealized condition where there is no grid current flowing at Vgk=0.

From 1 & 2 you can equate output power to voltage gain if you know the load resistance by stating:

2.82 SQRT(PoRl)= M =(Emax-Emin)/2Ec1

Rearanging you get Po=((Emax-Emin)/2Ec1*2.82)^2)/Rl
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