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#1 |
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diyAudio Member
Join Date: Jan 2008
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Hi,
I have dilemma, which of the posted variations is better? If the pot is dc connected directly to the grid isnīt the 50k too low for the tube as tubes have high impedance grids, right? So the first variant is better than? Thanks. |
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#2 |
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diyAudio Moderator
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Pots should never have DC on the wiper (or rather DC current to flow in the wiper no matter how small). That's a big reason for noisy crackly controls.
Also anything with DC applied to the input would alter the bias set up anyway. So yes, option 1
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------------------------------------------------------- A simulation free zone. Design it, build it, test it. |
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#3 |
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diyAudio Member
Join Date: May 2007
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Option 1 is best, but not for the reason the OP suggested. 50K is fine as a grid resistor, although lower than often used. Mooly is right - DC through the wiper is the main issue.
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#4 |
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diyAudio Member
Join Date: Jan 2008
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I didnīt make myself clear. I do not have any DC on input pot. But for the tube is it better that tube have 1M grid leak resistor or it can be small from 0k to 50k and it will not effect tube performance?
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#5 |
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diyAudio Member
Join Date: Sep 2003
Location: Midland, Michigan
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If it's a grid leak resistor, it needs to be 1meg or higher. Circuit 1 is best.
If you have a cathode resistor which lifts the cathode above ground, the 50k pot will provide the necessary grid connection to ground. Even so, it's a good idea to install a resistor from the grid to ground for protection in the event that the pot fails.
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Frank |
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#6 |
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diyAudio Member
Join Date: Feb 2009
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Simple SE schematic
visual of what frank is talking about. If you need a cap it should be after the pot if the source is already cap coupled. If the source doesnt have an output cap then you want it before the pot. |
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#7 | |
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diyAudio Member
Join Date: Jan 2008
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Quote:
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#8 | |
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diyAudio Member
Join Date: Jan 2008
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Quote:
But the coupling cap introduces some tiny distortion and you'd prefer not to have it. In that case change the pot to a stepped attenuation switch. These stepped switches are electrically just like a pot but don't have the static problem. Or maybe you never intend to use the volume control on a power amp. It's something you adjust one and leave alone for weeks at a time, so crackle and static are not issues. then #1 would be OK. Guitar amps solve this problem nicely by using option #3 "none of the above" and placing the "volume" control after the first tiode gain stage. (The reason is that these amps need to have a 1M or higher input impedance and you can't get that using a volume pot on the input jack) It turns out you need a coupling cap between stages so it does double duty to also keep DC off the pot, so no added cap. But for HiFi where to have a good line level source just go with #2. |
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#9 |
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diyAudio Member
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None of the above. I do this: (attached). Use a 100K linear pot, and parallel it with a 16K8 resistor. That not only gives you a log taper function, it also provides a guard resistor that will keep the grid connected to DC ground should the pot fail open. Linear pots aren't as liable to go scrathcy as log taper pots.
If you are absolutely sure you will never connect to anything that has a DC offset, you might be able to remove the coupling capacitor. (In this case, R2 is a 56R resistor to keep the pot from "bottoming out" to prevent those annoying speaker pops when the pot hits bottom. You may or may not want to include it.) Last edited by Miles Prower; 2nd August 2011 at 08:48 PM. |
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#10 | |
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diyAudio Member
Join Date: Jan 2008
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Quote:
If the resistor is larger than 2.2M the grid becomes "grid leak biased". Where it collects enough charge to effect the bias |
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