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Old 31st May 2011, 02:34 PM   #1
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Default Help to find out what OPT are these

Guys,

I lately was gifted a pair of big opt, and they are 3"x4"x3.5" H.
There are 3 wires on one side and 4 on the other. I did some measurement, both are identical.

Yellow - Green 367.1 Ohm
Y.... - Red 187.2 Ohm
Green - Red 180 Ohm

Black - Grey 0.6 Ohm
B.... - White 0.5 Ohm
B.... - Green 0.8 Ohm

Please help to find out they are PP, and or SE w UL ??? How many K at primary.

Thanks

Albert
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Old 31st May 2011, 02:38 PM   #2
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I tried to upload the photo. It said 'done', but nothing show on the first post. I'll try one more time later.
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Old 31st May 2011, 03:02 PM   #3
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Put Mains voltage (110 or 230 ? pls tell us) on Yellow and Green and tell us the voltages you mesure on the secondary side.
Measuring just DC resistance won't help you to find the Z cause it depends on wire length and gauge and is thus under-determined. So we must know the ratios !
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Old 31st May 2011, 03:37 PM   #4
DHT112A is offline DHT112A  United States
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A muck safer way:

OTimpedance
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Old 31st May 2011, 04:08 PM   #5
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It looks like a push-pull transformer with multiple secondaries

Do you have a signal generator and a true RMS meter or o'scope ?
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Old 31st May 2011, 04:33 PM   #6
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Albert,

What you have here are obviously PP output transformers (w/o) screen taps with a secondary of three output impedances. First, you must determine the turns ratio from the full primary to the three secondary output leads. From this you can determine the primary impedance using the formula Zp=N^xVp/Vs; that is assuming that you know the secondary impedances. The secondary impedances are likely 4, 8 & 16 ohms, but this is only a wild first guess; they could be different, but this is a starting place. The secondary common is likely the black wire. The white could be a 4 ohm tap, the grey an 8 ohm tap and the green the 16 ohm, but this is only a first guess. If the output voltage on the assumed 4 ohm tap is 1/2 the voltage of the assumed 16 ohm tap while the 8 ohm tap is .707 of the 16 ohm tap voltage then there is a fair chance that you have assumed correctly. I would not recommend applying the mains voltage to the primary as an inadvertent short could destroy the transformer or worse rather use a signal generator. If the calculated primary impedance is the same, say, 5,000 ohms or thereabouts from the three output taps then you likely have assumed the correct secondary impedances. Drive the secondary (assumed 8 ohms) with a largish SS amp while noting the waveform on a scope and determine the maximum power capability at, say, 20 Hz (which will be where the waveform starts to distort). If the maximum Po roughly corresponds with other known output transformers of equivalent size then you likely have guessed correctly. Then load the 8 ohm tap with an 8 ohm power resistor and drive 1/2 of the primary with a 1 - 5 kHz square wave (directly by a 600 ohm generator - to roughly simulate the rp of a DHT) and note the overshoot and ringing characteristics. Then, using a sine wave determine the -3dB HF roll off point. If it is ~20 kHz or higher then they could be used with triode power tubes. If substantially lower then they are suitable only for pentode operation.
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Old 31st May 2011, 05:44 PM   #7
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Albert,

The formula in my previous post inadvertently omitted the 2 in the N^2 (N squared) part of the equation, plus I apparently jotted the formula down w/o thinking. In any event, N=Vp/Vs. Zp=N^2*Zs. Or Zp=(Vp/Vs)^2*Zs. It is most convenient to make up a little three row spreadsheet to do the primary impedance calculations for each of the secondary taps using their assumed impedances and voltage measurements. If you have guessed the secondary impedances correctly the taps will all indicate the same primary impedance, if not then you can easily juggle the secondary impedance values to make them all come out equal. This is much quicker and and easier to make everything jive than doing it long hand or with a calculator.

Dan
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Old 31st May 2011, 06:41 PM   #8
taj is offline taj
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As a cheap and easy alternative to line voltage or a signal generator, if neither of these is practical, one could use an AC step-down transformer or wall-wart power supply of known voltage, correct? (Stressing, of course, that it's confirmed to be an AC supply, not DC.) Then derive the turns ration from that.

These are not uncommon in 12, 16, 24 VAC sizes. Maybe there's something in your junk box.

..Todd
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Old 31st May 2011, 09:02 PM   #9
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Quote:
Originally Posted by DHT112A View Post
A muck safer way:

OTimpedance
Big thanks. I'll try it out
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Old 31st May 2011, 09:07 PM   #10
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Quote:
Originally Posted by mdaniel7 View Post
Albert,

The formula in my previous post inadvertently omitted the 2 in the N^2 (N squared) part of the equation, plus I apparently jotted the formula down w/o thinking. In any event, N=Vp/Vs. Zp=N^2*Zs. Or Zp=(Vp/Vs)^2*Zs. It is most convenient to make up a little three row spreadsheet to do the primary impedance calculations for each of the secondary taps using their assumed impedances and voltage measurements. If you have guessed the secondary impedances correctly the taps will all indicate the same primary impedance, if not then you can easily juggle the secondary impedance values to make them all come out equal. This is much quicker and and easier to make everything jive than doing it long hand or with a calculator.

Dan
Dan,
My friend has a signal generator and scope. Might be I can ask him to help with this.

Thanks you all for the input
Albert
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