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Old 11th December 2011, 05:48 PM   #491
SY is offline SY  United States
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SY, Thevenin's theorem relates to any two nodes in any linear circuit. It does not address pairs of equivalents in a single circuit.
Never said it did. Figure 3. Try to count to two.
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Old 11th December 2011, 05:59 PM   #492
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Sorry, I can't follow your logic. Let's take it step by step.

Thevenin applies to two nodes and two nodes only.

Which pair of nodes do you want to analyze first, p&k, p&gnd, or k&gnd?
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Old 11th December 2011, 06:43 PM   #493
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OK guys, it's been fun and educational. I've gained some valuable insights from all this.

Signing off...

AC
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Old 11th December 2011, 08:27 PM   #494
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Which pair of nodes do you want to analyze first, p&k, p&gnd, or k&gnd?
They can be done simultaneously, if you wish. Nothing prevents that- this isn't quantum mechanics!
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Old 11th December 2011, 09:17 PM   #495
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I do not wish, because I suspect that that would violate Thevenin. Please choose the first node pair to analyze.
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Old 11th December 2011, 09:22 PM   #496
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k&gnd!
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Old 11th December 2011, 09:22 PM   #497
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Ah, so we've now moved from the "I can't count to two" problem to the "I want to violate the boundary condition" problem. Pick one and stick with it.

If you short one output, you have to short the other. That's the "given." If you can't accept the given, then you have no valid critique of my results given the given.
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Old 11th December 2011, 09:36 PM   #498
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No, SY, that is an incorrect analysis.

I understand your "given" to be that I must always keep the Cathodyne balanced, not that I must short the p & k to ground. Or has the "given" changed?

If I acceed to your demand that I satisfy what I understand to be your "given", an always balanced Cathodyne, then surely it is a small effort on your part to agree to adhere to Thevenin. You can't sacrifice Thevenin on the altar of your boundary condition.

Short the p to the k only. Satisfy your boundary condition, and Thevenin at the same time, and be done with it. Arrive at Vogels result.
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Old 11th December 2011, 09:47 PM   #499
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Quote:
Originally Posted by SY View Post
Never said it did. Figure 3. Try to count to two.
If figure number is 3 we should count to 3, no?
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Old 11th December 2011, 09:48 PM   #500
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Quote:
Originally Posted by CPaul View Post

I understand your "given" to be that I must always keep the Cathodyne balanced...

...your "given", an always balanced Cathodyne
Apparently you don't.
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