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Old 13th March 2011, 05:37 PM   #1
Minion is offline Minion  Canada
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Join Date: May 2006
Default simple heater question .....

Hi guys , here is a stupidly easy question for you ......

I"m running 6.3v AC heaters and the data sheet for the 12ax7 says that at 6.3v the heater draws 300ma Current ...... is that 300ma (150ma per triode) per tube or 300ma per triode (600ma per tube) .......

I need to know becasue my 6.3v tap is putting out 7.75v under a load (2 x 12ax7) and I need to calculate what resistor to use to drop it to 6.3v ....


thanx
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Old 13th March 2011, 05:54 PM   #2
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Each section of the 'X7 draws 150 mA. of heater current. Connect the sections' heaters in series and you need 12.6 VAC/150 mA. Connect the sections' heaters in parallel and you need 6.3 VAC/300 mA.
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Eli D.

Last edited by Eli Duttman; 13th March 2011 at 05:55 PM. Reason: fixed typo
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Old 13th March 2011, 05:58 PM   #3
Minion is offline Minion  Canada
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Thank you very much ...... I"m connecting two 12ax7 tubes in paralell , so 2 tubes or 4 sections will draw 600ma total ..... Thanx a lot
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Old 14th March 2011, 03:28 AM   #4
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Well stated, Eli.

P
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