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#1 |
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diyAudio Member
Join Date: Jan 2009
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First,
I am finishing up the design of my "new" system. I have come to some "sticking points" as to overall design and need some info/advice on how I should proceed. The source I plan to use most (90%) of the time is a Behringer FCA-202 Firewire Interface using low latency ASIO drivers on a PC. This interface can output either balanced or unbalanced. Because of limitations using ASIO on a PC, I will have no "Master Volume" control at the source. (anyone using a PC as a source and ASIO will understand) but in a nutshell, some applications can control volume with ASIO but windows itself does not, so...if your using the "system" as your PC speakers you end up with all kinds of crazy levels and ideally you really do not want anything between the source digital material and the outputs. I also plan to sometimes us vinyl and broadcast radio as sources. Here are my dilemmas, Immediately following the source(s) I plan to use a 2-way 24db/Octave LR active Xover using Opamps. The lows going to SS amps and subs. The Hipass will then be split again @ about 2.5khz via a Pete Millet design all tube Xover. Those outputs going to PP 807 "Williamson" amps for biamping. So the main issue is this, Ideally I would like to use "balanced" inputs into the SS Xover, the PCB has provisions for this and since the source might be a good ways away from the amps physically it makes sense. BUT, 1. How to attenuate a balanced source easily using pots? 2. Most of the tube RIAA preamps designs I see are SE without Balanced outputs, so with the Xover built for balanced in's how to "balance" the outputs of the phono preamp and the other possible sources? (I would rather stay away from $$$$ trannies on the preamp. Could I just use a rather low RP triode in a "split load" phase inverter layout with rather large coupling caps to prevent a low end roll off? Attached is possible configuration, still need to know how to attenuate that level. |
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#2 |
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diyAudio Member
Join Date: May 2007
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To attenuate a balanced signal with pots you need a pair of pots per signal, so four pots for stereo.
A balanced input will always accept an unbalanced signal. Just connect + to signal in, - to ground in. I can't help any more, as I would not start from where you are! |
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#3 |
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diyAudio Member
Join Date: Jan 2009
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#4 |
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diyAudio Member
Join Date: May 2007
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It's just that my system is much simpler. Sources (all unbalanced), switch/pot box (i.e. 'passive preamp'), valve amp, speakers. That's all. I prefer simplicity.
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#5 |
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diyAudio Member
Join Date: Apr 2003
Location: Eastern Pennsylvania
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That phase-splitter you show does not produce a balanced interface. While the tube stage shows matching resistors connected to the plate and the cathode, the net impedance at the plate and cathode terminals will be very different. Yes, the signal will be differential in phase, but not balanced in impedance - Which is what defines a balanced interface. If you are truly after the noise cancelling benefits of a balanced interface, then transformers (sorry) at both ends is about optimal.
Since your diagram shows, however, that you plan to convert the differential signal back to single-ended at the far side of the interface, another effective, but inexpensive option is to use a single-ended (tube or otherwise) output stage instead of the phase-splitter to drive one phase of the differential line. Then, at the near side, connect the oppositely phased line to ground via a passive RCL network whose impedance matches that of the driven phase. For example, if you have some single-ended tube gain stage featuring a 15K ohm output resistance driving the positive-phase leg of the interface through a 10uF A.C. Coupling cap., then you would connect the negative-phase leg through a 15K resistor and 10uF cap. wired in series to ground.
__________________
Ken |
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#6 |
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diyAudio Member
Join Date: Jan 2009
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Ironically, two years ago the "plan" was a more simplistic version. If I could get to where I want to go that simply trust me I would.
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#7 | |
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diyAudio Member
Join Date: Jan 2009
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Quote:
Let me get this straight. Assuming a proper switch gear I can run XLR jacks with my balanced signal to the inputs of the buffer as shown from my soundcard. Then I can "switch in" the "unbalanced" input of the other sources to the Positive phase input and then couple the negative phase thru the same value cap and output resistance. My question is are we taking output RESISTANCE ie; the resistor from junction of the coupling cap and output to ground or Zout Output IMPEDANCE of that stage? |
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#8 |
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diyAudio Moderator
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Ken, as long as the loads are balanced (VERY important!), the impedances are balanced. The only nonideality is the difference in power supply rejection at the plate versus cathode. See my article in the first issue of Linear Audio for experimental verification.
The circuit as drawn, however, is severely flawed and will have high distortion. The grid needs to be referenced to a voltage approximately 1/3 of B+.
__________________
“Listening to records is like ****ing a picture of Brigitte Bardot.” - Sergiu Celibidache |
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#9 | |
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diyAudio Member
Join Date: Jan 2009
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Quote:
You are right!! It was an oversight on my part, I mean't to reference it to the cathode !!! 0 Volts bias for 10mA Current. It would have like 90 volts bias referenced to ground!!! It was just a thrown together circuit to show my intent would not have been built like that. I assume it would work the same if the driving stage was a cathode follower? Since it will be at the tail end of a phono stage I will have a very QUIET (hopefully) B+ source. |
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#10 | |
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diyAudio Member
Join Date: Nov 2007
Location: Dallas
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Quote:
1/2 Mu follower at emitter , 1/2 Schade follower at collector. Both ends having voltage gain of about 50 with 12AX7 triode. Results almost same as long tail pair except: No cancellation of the 2nd harmonic, no need for negative rail, triode operates on its own CCS slope rather than sharing current vs another triode. When plate and cathode voltage feedback have equal influence, you will observe the "tail" swings 1/2 the input. Just like a LTP. Notice the ratio of R2/R1 = Mu required for impedance match. Sorry, direct coupled cathode feedback requires P Sand to flip the phase. Anything N here just wouldn't have worked... There aren't a great many choices in P. MJE350 may work (300V 20W) if you can't find MJE15035 (350V 60W TO220). The other Ken Last edited by kenpeter; 8th February 2011 at 03:18 PM. |
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