Function of R2
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 1st December 2010, 09:58 AM #1 studiostevus   diyAudio Member   Join Date: Oct 2009 Location: Brunei Function of R2 Hi, Newbie alert: I am planning on designing a anode follower as an output stage to my tda1541 dac. I was planning to use this topology, but was wondering about the purpose of R2, and how to calculate appropriate values. Is it a simple grid leak? Morgan Jones does really describe the anode follower (don't know why), so any help is appreciated. Thanks
 1st December 2010, 10:56 AM #2 Gilgy   diyAudio Member   Join Date: Oct 2009 R2 is there to provide negative feedback - good explanation here Designing Single-Stage Inverting Feedback Amplifier
 1st December 2010, 11:02 AM #3 DF96   diyAudio Member   Join Date: May 2007 R2 is the feedback resistor. To a first approximation, voltage gain = -R2/R1 (like the inverting op-amp). In that circuit it is also arranged to be part of the grid leak via RL, but you could do it differently if you wanted. R1 sets the input impedance - generally as low as possible for most current-output DACs. You could even try omitting R1, then you have a transimpedance stage (current in, voltage out). Input impedance would then be roughly R2/mu - which could still be too high for the DAC chip. Many circuits seem to get away with violating the DAC data sheet requirements - whether this is because DACs are more tolerant than their makers suggest, or people who fiddle with DACs are more tolerant of distortion than they realise I am not qualified to judge.
 1st December 2010, 11:04 AM #4 Yvesm   diyAudio Member     Join Date: Jul 2004 Location: Ardeche R2 is the feedback resistor wich sets the gain as being roughly (R1 + R2) / R1 providing that the gain you need is lower (says 1/20) than the Mu of the triode. Output and input impedances decrease as much as this ratio is high so, without R1 (understand 0 ohms) the input impedance fall down and it's probably what your TDA1541 expects for good linearity. Yves.
 1st December 2010, 12:53 PM #5 DF96   diyAudio Member   Join Date: May 2007 Not (R1+R2)/R1, but roughly R2/R1 as I said - assuming sufficiently high open loop gain (equivalently, mu and appropriate load impedances).
 1st December 2010, 02:37 PM #6 Yvesm   diyAudio Member     Join Date: Jul 2004 Location: Ardeche In you, I trust
 1st December 2010, 04:48 PM #7 Miniwatt   diyAudio Member     Join Date: Nov 2004 Location: Den Haag Which tube are you using?
 1st December 2010, 05:13 PM #8 no gas   diyAudio Member   Join Date: Jul 2010 Location: Los Angeles And all this time I thought R2 was the little droid in Star Wars! __________________ My stuff: MC30, MC225, MX110, PAS3, ST-70, RH-84, HK A224 and a lot of parts waiting for time.
 1st December 2010, 05:49 PM #9 studiostevus   diyAudio Member   Join Date: Oct 2009 Location: Brunei I have some 6n16 submini's as well as some 6n2p's... I will try to use 6n16 first, but havent done the calculations yet as to gain.
 5th December 2010, 08:23 PM #10 studiostevus   diyAudio Member   Join Date: Oct 2009 Location: Brunei Allright, so I have done the math, but not sure of some things. img31.gif 1. The value of R2 seems very high, and does not fit with your role of thump R1/R2=gain. I have calculated it using the formula on the aikenamps website (Rf = ( ((Ri+Ra-(Ri*A))*Acl)-Ra ) / (A-Acl). I will use 2 parallel tda1541, so i/v converter of 28R is appropriate. That means I will be looking for A=12.4=Vout/Vin to get to 2Vpp on the output. 2. I was wondering about the 2mA 'DC' offset that the tda produces. In this setup, will that be present on the output? as there is no cap to block dc coming from the grid. BTW the 6n16 datasheet is here Thanks for the help!! Last edited by studiostevus; 5th December 2010 at 08:36 PM.

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