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Old 8th July 2003, 08:24 PM   #1
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Default How do you use a 0D3 regulator?

Now I am still im my infancy with regard to tubes. So I apologize to anyone offended by my stupid questions here.

I found a 0D3 regulator tube or so I am told. I was wondering if I can use it in a preamp that I plan to use. I need about 144-150 or so volts on the plate of a 5687 tube for this project. My power supply is going to be a 300-0-300 transformer followed by a 30H 40ma choke, a 50mfd/500 cap, a 30H choke, and a 50mfd cap. I'm going to guess that I will be somewhere around 220 volts B+ here. I will need to drop off the excess voltage so I will need to figure a resistor. The tube I am assuming will draw about 12MA. per section?

Now, can I use the 0D3 in place of the voltage dropping resistor to end up with my 150volts? I am told it will give 150volts out. If so how do I wire it up? Or am I trying to do something very stupid here?

Frank? anyone?

Thanks
Joe
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Old 8th July 2003, 08:43 PM   #2
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What you have to do is put a bias resistor from B+ to the plate of the tube and then wire the cathode to ground. The resistor will drop the B+ voltage difference from what the OD3 drops. I'm not sure what B+ you are using, but you have to decide on what resistor to use to drop the voltage at an acceptable rate without dissipating too much heat. Also, put a small cap accross the OD3 from plate to cathode, this will minimise the terrible noise some OD3's make.

This tube works exactly like a zener diode and all you need is a resistor to use it in the amp, the cap is an option and will improve the noise floor of the amp.

Hope this helps. If you need better ideas, I can draw you a diagram give you examples of what resistor to use.
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Old 8th July 2003, 08:58 PM   #3
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Duo

Thanks for the reply. A schematic would indeed be nice. Maybe there are others out there that would also benefit from the knowledge that you could share.

I have downloaded Duncans PS designer but haven't quite figured out the workings of it yet.


Joe
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Old 8th July 2003, 09:01 PM   #4
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Hi,

Quote:
Now, can I use the 0D3 in place of the voltage dropping resistor to end up with my 150volts? I am told it will give 150volts out.
The OD3 is a mercury vapor cold cathode voltage regulator suitable for 150VDC at 40mA max.

It needs a striking voltage ( igniting it) of 185V min. so, yes this should work.

You'll need to calculate a dropper resistor to arrive at the "striking" voltage ( a little higher won't hurt but too low and the tube won't light up) using Ohms' law.

It is also recommended to decouple the tube using a 0.100uF filmcap (max) to prevent the tube from oscillating.

Just like a zener it will try to clamp the output at 150V.

OD3

Check the eye icon for pinout, "stabiliser" for technical data.

A more recent variant but much lower current is the OA2.

I have no hands on experience with the OD3 but noticed David Manley uses some in a preamp...

Cheers,
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Old 8th July 2003, 09:28 PM   #5
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Frank

As always thanks for the help. Do you happen to have any schematics from David Manley? I was able to get the tube base as 4AJ. I can't seem to find any other data.

In your opinion is this a good idea or one that I should drop?



Joe
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Old 8th July 2003, 09:51 PM   #6
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Hi,

Quote:
I can't seem to find any other data.
I don't know what you need, this kind of tube only consist of an anode, a cathode and gas.

From the link posted you can easily figure it out:

From browser menu, edit, find on this page: 4AJ.

Quote:
Do you happen to have any schematics from David Manley?
Nope...does anyone? I worked closely with the importer... never saw a single schematic form Manley other than those published in a little book he once published and that's years ago anyway.

Quote:
In your opinion is this a good idea or one that I should drop?
It doesn't cost an arm and a legg to try out so why not give it a go and see what you like best?

Cheers,
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Old 8th July 2003, 10:34 PM   #7
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I believe the OD3 is actually a Krypton tube, not Mercury Vapour.

At the moment, I have nothing on this computer to use for drawing a schematic of the OD3 setup. However, for calculating the resistor, find out the idle current of the tube and calculate for a resistor that maintains just above whatever output current you intend to use for the specified voltage drop. You will need a power resistor here since over 100V at 15 - 40 mA will give in the vicinity of 2 - 4W of dissipation.

As soon as I get to a computer that has what I need to make the diagram, I'll draw it for you.
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Old 8th July 2003, 11:19 PM   #8
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Hi,

Quote:
I believe the OD3 is actually a Krypton tube, not Mercury Vapour.
I think you're absolutely correct.

My source stated mercury vapour which made me frown...

We have the following gasses in this type of cold cathode tubes:

Neon, Argon, Krypton and possibly a combination of them, although I somehow doubt the latter.

The OD3 hasn't seen much use in audio circuits throughout the history but has been used in scopes and regulated benchsupplies...

Indicating only 9 and this is just an educated guess) that it was considered too expensive by engineers to use in what they quite likely considered to be "inferior" audio circuits.

Nowadays, gasregs are relatively cheap and have every potential to lift an ordinary circuit to exceptional levels...and they're much less noisy than most zeners.

Guess you know where I stand on this by now?
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Old 8th July 2003, 11:26 PM   #9
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Thanks for the help here. A schematic would be helpful since I am not functioning too good today. Its amazing that taking a few days off can seem like more work than actually going to the job. I had a nice day planned in the garage only to have my plans restructured by the wife. She got her work done, mine is still setting there unfinished.

Frank

I figured what pin 5(anode) is and pin2(kathode) pins 3 and 7 are marked J. What is J?

Sorry, its been a long long day.


Joe
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Old 8th July 2003, 11:40 PM   #10
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Hi,

Quote:
She got her work done, mine is still setting there unfinished.
Why does that sound so familiar?

Quote:
I figured what pin 5(anode) is and pin2(kathode) pins 3 and 7 are marked J. What is J?
I was wondering about that too...don't take my word for it but I think it means " internally connected".
If this is so, you'd better leave those alone.

I'll see if I can find the appropiate info in one of my databooks for you...so hang in there.

Oh, I see I have meetings scheduled for tomorrow, in fact for most of the week...maybe someone could be so kind to look this up for Joe?

Cheers,
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