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Old 22nd June 2003, 03:37 PM   #11
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Hi,

Quote:
Regarding the 10W resistor. Well the max I can find locally is a 5W ceramic resistor. good enough?
5W on its' own, no.
Here's what you can do, assuming a fictitious value required of 1 Ohm/10W you can use 2 2Ohm/5W resistors in //.

BTW, it doesn't have to be a ceramic one, you can probably source 10W or higher wirewound ones?
Most of those have a heatsink that allows you to srew them to the chassis for better cooling.

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Old 22nd June 2003, 03:45 PM   #12
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Jayel,

The purpose of a reservoir (tank) cap is to remove any ripple from the DC output of the rectifier. I've dropped you an e-mail on the minimum changes needed for you to use a 6X5GT in preference to a 6X4.
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Old 22nd June 2003, 04:04 PM   #13
jarthel is offline jarthel  Australia
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Quote:
Originally posted by fdegrove
Anyway, you can use an LC filter instead of the CLC filter you now show.

Suppress the first 100 uF cap... you can put it behind the self if you like...
The 470K R you can put across the last cap where it will serve as a bleeder.

100 Ohm resistor can be removed as well, the circuit will have a slow start as it is already.
with the recommendation of using an LC filter instead of CLC and the removal of 100 ohm resistor, the circuit now becomes:

6X5GT -->> choke -->> capacitor -->> resistor -->> capacitor

Is this correct?

also, do I change the capacitor values with the change to LC?

thank you.

jayel
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Old 22nd June 2003, 04:12 PM   #14
jarthel is offline jarthel  Australia
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Quote:
Originally posted by fdegrove

Here's what you can do, assuming a fictitious value required of 1 Ohm/10W you can use 2 2Ohm/5W resistors in //.
wouldn't 2 20ohms 5w in parallel be equal to a 10ohms 5 w resistor?
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Old 22nd June 2003, 04:18 PM   #15
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Hi,

Quote:
Is this correct?
Indeed, it is. You go from CLC to an LCR type of filter.

Quote:
also, do I change the capacitor values with the change to LC?
Quite likely there won't be any need to do so.
Although the values don't have to be that high I don't mind a bit of a "brute force" approach.

You could do a sim on PSU Designer and it wouldn't surprise me one bit if it'd spit out much smaller value caps.

Either way it won't do any damage.

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Old 22nd June 2003, 04:21 PM   #16
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Hi,

Quote:
wouldn't 2 20ohms 5w in parallel be equal to a 10ohms 5 w resistor?
2*20R/5W in // will yield 10R/10W since they will share the dissipation between them.

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Old 22nd June 2003, 04:27 PM   #17
jarthel is offline jarthel  Australia
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Quote:
Originally posted by fdegrove

Indeed, it is. You go from CLC to an LCR type of filter.
Is there any advantage of using LCR to CLC? Also is there anything wrong with the circuit I posted except for the fact that I'll be using a 6X5GT. I know you mentioned removing the 100 ohms and replacing the 470K after the last capacitor. anything else?

Thank you.

jayel

ps. I'm not trying to question your response. It's more like understanding on how you came up with such a response which would help me understand circuits more.
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Old 22nd June 2003, 04:47 PM   #18
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Hi,

Quote:
Is there any advantage of using LCR to CLC?
Depends on what you're targetting.
The CLC may have slightly better ripple rejection.
You could give it a try but you'll need a DVM at least to see what gives the best results.


Quote:
I know you mentioned removing the 100 ohms and replacing the 470K after the last capacitor. anything else?
Well, there's that cap directly after the 6X5 of course, either remove it altogether or move it after the choke where you can make another RC filter cell.

Quote:
ps. I'm not trying to question your response.
No problem.

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Old 22nd June 2003, 10:03 PM   #19
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Default Re: is 6X5 an octal 6X4?

YES. In fact they often use the exact same electrode structures.

Tim
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Old 22nd June 2003, 10:50 PM   #20
jarthel is offline jarthel  Australia
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Quote:
Originally posted by fdegrove
2*20R/5W in // will yield 10R/10W since they will share the dissipation between them.
Well you first mentioned the value 1ohm 10W resistor. Why can't I use 2ohm 5W in parallel?

Thanks

Jayel
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