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#1 |
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diyAudio Member
Join Date: Aug 2005
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I want to use a different tube that uses a 6.3V filament. I have a 12.6V supply but the reg is adjustable.
What resistor changes ie values do I need for the resistor divider network that is in there now. It has a 200R and a 2K. Schematic attached. Much appreciated! |
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#2 | |
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diyAudio Member
Join Date: Feb 2009
Location: Greater Seattle Area
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Quote:
~Tom |
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#3 |
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diyAudio Member
Join Date: Aug 2005
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Thanks Tom! My math is horrible but I give it a go since the formula is there. I have values in there as reference for calculation for 12.8V
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#4 |
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diyAudio Member
Join Date: Aug 2009
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#5 |
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diyAudio Member
Join Date: Jul 2009
Location: Cheltenham
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I dont know what current you need? but be sure you dont run the 317 too hot
![]() Cheers Matt. |
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#6 |
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diyAudio Member
Join Date: Aug 2005
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WOW! The calculator is awesome. Looks like R2 or in my case R11 is 810R I get 6.3V
I don't think it will run too hot. |
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#7 |
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Banned
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How much current?
If the tube is equivalent, then the current will be ~double that in the original circuit. The voltage dropped across the 317 will be 6.3 volts higher. So the dissipation in the 317 will be ~4 times the original. Has it got a heatsink? 400% could be too much... w |
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#8 |
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diyAudio Member
Join Date: Aug 2005
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It does have a heat sink. I need to investigate this. Thanks for the reality check on this.
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#9 |
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diyAudio Member
Join Date: Aug 2005
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I was using a 5965 and will be moving to a tube with the following specs:
Uf = 6.3V, If = 350 mA uM = 25 Ia = 10.5 mA S = 6.8 mA/V Pa = 1.5 W I have two filament supplies. One for each tube. |
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#10 |
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diyAudio Member
Join Date: Aug 2005
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One last question. If I do run into heat issues with the reg can I go to a LM335T and have the same voltage divider resistor values?
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