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Old 23rd March 2010, 01:51 AM   #1
losacco is offline losacco  United States
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Default Resistor wattage?

My project calls for a 24k 1w resistor, if I use 2 12k resistors, do they need to be 1/2 w each to equal 1w?
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Old 23rd March 2010, 01:56 AM   #2
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Yes

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Old 23rd March 2010, 04:49 AM   #3
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losacco,

While two 12k, 1/2 watt resistors in series will give you a resistance of 24k they will only be able to carry 1/2 watt of current. You either need the proper resistor or two 48k, 1/2 watt resistors wired in parallel. That way each resistor carries 1/2 the current & you end up with the equivalent of a 1 watt resistor.

Do a google search for "resistors in series" and read a few of the articles. Understanding series and parallel circuits is essential for our hobby.
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Old 23rd March 2010, 07:04 AM   #4
chrish is offline chrish  Australia
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Quote:
Originally Posted by ronaldw441 View Post
losacco,

While two 12k, 1/2 watt resistors in series will give you a resistance of 24k they will only be able to carry 1/2 watt of current. You either need the proper resistor or two 48k, 1/2 watt resistors wired in parallel. That way each resistor carries 1/2 the current & you end up with the equivalent of a 1 watt resistor.

Do a google search for "resistors in series" and read a few of the articles. Understanding series and parallel circuits is essential for our hobby.

Last time I checked, current was measured in Amps, not Watts. Watts is a measure of power.

Yes, two 48K resistors in parallel will do the job, as you describe, each resistor carries half the current.

The original question, can two 12k 1/2 watt resistors in series replace a 24K 1 Watt resistor. The answer is YES. Each of the resistors will pass the full current, but as they have half the resistance, they will each drop half as many volts as the original, and therefore each will dissipate half the power.

So, in short, either two 12K 1/2 W in series, or two 48K 1/2 W in parallel will work.

Regards,

Chris
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Old 23rd March 2010, 07:33 AM   #5
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Chris,

Good point.

Thank you,

Ron
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