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#1 |
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diyAudio Member
Join Date: Feb 2010
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On the attached circuit the +B is 250V -
C4 is 1,0uF and is calculated to -3dB at 20Hz when "looking" into 100K pot. R11 is 470K. R4 and R9 is 30K/2W - R 12 is 1K C7 and C8 is 10uF/400V. R3 and R10 is 500R parallel with 100uF/10V Anyone who has the math formular to calculate the -3dB point (depending on C4) ? The lineamp might be the Aikido. Have already one 100K ALPS log. stereo pot. Gudmund |
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#2 |
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diyAudio Member
Join Date: May 2007
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-3dB LF point at output is given by 2 pi f = C4 x ( R9||Ra + 470K||100K), where Ra is the anode impedance of V2, and Rx||Ry means Rx and Ry in parallel.
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#3 |
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diyAudio Member
Join Date: Feb 2010
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#4 | |
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diyAudio Member
Join Date: Feb 2010
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Quote:
Could you please let us have your opinion ralated to the phono circuit? Is it worth working with? - The phono riaa is used only occational - the Aikido phonostage uses more tubes for the same funktion.- Would like to keep the phonostage simple. Gudmund |
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#5 |
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diyAudio Member
Join Date: Feb 2010
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Anyone - please let us have your opinion related to the phono circuit? Is it worth working with? - The phono riaa is used only occationally - the Aikido phonostage uses more tubes for the same funktion.- Would like to keep the phonostage simple.
Gudmund Nb. Anyone who has the formular to calculate C3 and R7 on the attached circuit? |
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