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#1 |
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diyAudio Member
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I am a newbie ... don't laugh ya !
OK ... wish to build a #26 linestage but having problem getting the 1.5VDC required for the #26 tube! Built Chris Brady's design : 5VAC~Schottky bridge~10K uf~0.47R~10K uf~LM1086~1.2R . I got 4.7VDC !? From here, how do I acheives the 1.5VDC@1A needed for the Type 26 tube? Thanks for looking & any help forecoming, Zekk |
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#2 | |
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diyAudio Member
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Quote:
Don't know about this design, but you mention the 1.2R resistor, and therefore I think the LM1086 is configured as a CCS (the 1.2R between adjust and output, and the tube filament fed from 'adj'). This means that the regulator will pass only 1A, which multiplied by the Resistance of the 26's cathode will develop 1,5V. Prior to testing that, just post the schematic! Erik
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my surname is indeed 'de Best': neither misspelling nor snobbism! Ask SY! |
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#3 |
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diyAudio Member
Join Date: Sep 2003
Location: London
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In principle that should work, with LM1086 as current source. that means 1.2R between adj and out pins. Be careful to take the output from the adjust pin!! This may be where you are going wrong.
To make sure you have enough headroom, just try taking the capacitor straight to the LM1086 input. you need about 4.5v going into the LM1086. I use a 6v secondary. But I suspect you've wired the LM1086 wrong, as above. andy |
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#4 |
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diyAudio Member
Join Date: Aug 2002
Location: Sofia
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And don't forget to measure the output voltage with a tube or equivalent resistor connected at output.
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#5 | |
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diyAudio Member
Join Date: Feb 2009
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Quote:
LM1086 is a low-dropout regulator so it only needs ~1.5V voltage above the desired output, which would explain your high voltage measurement (4.7V) with open terminals. By the way, make sure your LM1086 has some sort of cooling (= a suitable heatsink) as it is going to dissipate approximately 5 watts during operation. |
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#6 |
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diyAudio Member
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First and foremost, many thanks to all the kind soul out there who've given me the help to build this unique linestage.
Loaded with a 1.5R resistor as adviced and there it is, a 1.5VDC reading! Cheers! Zekk |
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