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Old 4th November 2009, 03:13 AM   #1
john65b is offline john65b  United States
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Default What happens when Heater Cathode voltage is exceeded?

Hey all,

I found a bunch of 5963 tubes at work (apparently 6.3v heater versions of 12AU7) and decided to build the attached schematic. With 250V B+ and the heater ground has been lifted about 70V.

Now the question, I have run through 3 tubes where the back side of the tube (plate pin 6 and cathode pin 8) have died after a couple hours. I have confirmed the backside of the dual triode (pin 6/7/8) is dead with a Tube tester. All I can think is that I possibly exceeded the Heater Cathode Voltage. Is this what happens when you exceed the max heater to cathode voltage?

The 5963 Heater pos/neg to cathode max voltage is 90V/90V, and I am right at 87V/80V after tweaking.

The intended tube is the 12AU7 which has a max heater pos/neg to cathode max voltage of 180V/180V...
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Old 4th November 2009, 03:38 AM   #2
kevinkr is offline kevinkr  United States
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Take one of these bad tubes and measure the voltages on all pins in circuit, and do the same with a known good one - the answer should then be quite obvious.

Failure under the conditions you describe is possible, but I have not run into too many cases where the failure was this extreme or rapid.

I would obviously recommend you get some 12AU7A/6189/5814 fairly soon.. (Watch the cathode/filament ratings though)
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Old 4th November 2009, 07:09 AM   #3
cerrem is offline cerrem  United States
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One thing to keep in mind with cathode follower... The cathode to heater difference is the sum of the AC signal voltage and DC voltage... You have the DC voltage difference which it looks like you accounted for...you need to add half the AC signal rms value to this.... or half of the max voltage swing you get from the gain of the first stage...

Chris
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Old 4th November 2009, 08:13 PM   #4
tomchr is offline tomchr  United States
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The heater and cathode are close together. My assumption is that exceeding the Vhk spec would lead to dielectric breakdown of whatever separates the heater from the cathode. Arcing would result. I doubt it would be enough to physically break the tube, but it would certainly screw with the performance and would likely strip off any coating on the heater or cathode, thus, making matters worse.

Those are my thoughts on the topic anyway.

~Tom
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Old 4th November 2009, 08:27 PM   #5
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A dielectric breakdown would fuse (permanant short) the cathode with the fillament. So it wold make the tube unoperable if the filament circuit is grounded. Or if is not, will raise all the other fillamens to that high voltage. And maybe damage the other tubes too.
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Old 4th November 2009, 08:55 PM   #6
john65b is offline john65b  United States
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With a fresh tube, I get 128V on cathode (pin 8) and 250 at plate (pin 6)...After a few hours of play with no issues, I shut the preamp down and go to bed.

The next day I start the pre and no or very low output. I open up the pre and check voltages and that Pin 8 cathode voltage is either 60V-70V or 0V, and 250V on plate.

I have gone through three 5963 tubes already. On tube tester, front side triode is fine, back side triode is dead.
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Old 4th November 2009, 09:38 PM   #7
SY is offline SY  United States
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Connect a diode between the grid and cathode of the cathode follower section. The diode's cathode (the end with the stripe) shoind be attached to the tube's cathode. Then see if your tubes survive the rigors of turn on and turn off.
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Old 5th November 2009, 12:38 AM   #8
wa2ise is offline wa2ise  United States
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You could rearrange things so one tube does the left and right channels of the bottom triodes, and the other tube does the top triodes. And feed both with separate heater supplies biased to close to where the cathodes will be operating at. Maybe (thinking out loud here, so this may or may not be a good idea) you can use a resistor of a few 100K's between the top triode cathode and the heater, and bypass the heater side of that resistor with a cap to ground. This will make sure that the heater bias always track the cathode voltage, if the time constant of the RC is long enough to smooth out the 60Hz AC heater supply (oh wait, you're using DC so that issue should go away) but short enough to allow the cap to charge up fast enough to let the heater bias track the cathode when it's heating up.
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Old 5th November 2009, 12:48 AM   #9
john65b is offline john65b  United States
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Quote:
Connect a diode between the grid and cathode of the cathode follower section. The diode's cathode (the end with the stripe) shoind be attached to the tube's cathode. Then see if your tubes survive the rigors of turn on and turn off.
Sy, Will a 1N4001 work OK? Connect from pin 7 to pin 8 (Diode of cathode to pin 8)

You think its a turn on/off inrush problem?
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Old 5th November 2009, 02:27 AM   #10
SY is offline SY  United States
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It's possible. You could be arcing the grid to the cathode, which (blush) I've done before I got wise and started using protection. In any case, I'm not sure what the voltage rating of the 4001 is, but if it's more than your B+, go for it. I typically use 1N4007.
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