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#1 |
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diyAudio Member
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I was reading "Designing Valve amplifiers" By Morgan Jones (Highly Recommended) and saw the page for cancellation using one valve, page 392.
I had some questions. First, would each winding be 2*RP as a rule of thumb? Would Av = 2 * mu/mu+1 ~ 1.8? The circuit looks like it might work great with a toroid and maintain "perfect" balance. It would also work with something like the Lundahl LL1663, but not most classic push pull transformers. I was thinking I could have a bit different amp. Any thoughts are appreciated. I was sketching concepts on my pad for this and thought I'd throw it out for comments. Doug
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Scienta sine ars nihil est - Science without Art is nothing. (Implies the converse as well) Mater tua criceta fuit, et pater tuo redoluit bacarum sambucus Last edited by DougL; 29th October 2009 at 11:44 PM. Reason: spelling |
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#2 |
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diyAudio Member
Join Date: May 2003
Location: Where you live
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Hello,
got any picture of the concept? - Elias |
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#3 |
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diyAudio Member
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I will Sketch one up today.
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Scienta sine ars nihil est - Science without Art is nothing. (Implies the converse as well) Mater tua criceta fuit, et pater tuo redoluit bacarum sambucus |
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#4 | |
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diyAudio Member
Join Date: Dec 2008
Location: United Kingdom
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Quote:
I think it could work well with triodes like the 6080/6AS7 that have a very low mu anyway.... Cheers, 45 |
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#5 |
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diyAudio Member
Join Date: Jan 2005
Location: Chicago
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It seems like such a nice concept. However, the problem is that the AC signals will exactly cancel each other out leaving you with almost exactly no output. That is, it is an error in the book.
Sims are from Slagle from a while back. Also, if you search AA for "chokertina" there was a discussion on this in 2003.
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http://www.ecpaudio.com |
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#6 |
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diyAudio Member
Join Date: Dec 2008
Location: United Kingdom
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I was thinking about something like the Klimo Beltaine. Using the 6AS7, one triode is the amplier and the other for the DC balance only. Cathode follower config. if you like. Probably it doesn't work as well because the DC side has to be a current source.
I don't have the book by Morgan Jones . Cheers, 45 Last edited by 45; 2nd November 2009 at 08:36 PM. |
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#7 |
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diyAudio Member
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Here is The Concept.
Push pull transformer with split, not center tap primary. Standing current cancels. And since there is only 1 tube and Icathode and IPlate are equal until A2, the current ballance should be "perfect". Morgan Jones said it was a problem to drive. Doug
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Scienta sine ars nihil est - Science without Art is nothing. (Implies the converse as well) Mater tua criceta fuit, et pater tuo redoluit bacarum sambucus |
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#8 | |
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diyAudio Member
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Quote:
Thanks. Sounded too good to be true. Doug
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Scienta sine ars nihil est - Science without Art is nothing. (Implies the converse as well) Mater tua criceta fuit, et pater tuo redoluit bacarum sambucus |
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#9 |
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diyAudio Member
Join Date: Jul 2009
Location: Cheltenham
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It should work. The ac signals at the anode and cathode are opposite phase right?
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#10 |
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diyAudio Member
Join Date: Dec 2001
Location: Hickory, NC
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"The ac signals at the anode and cathode are opposite phase right?"
Yes, but they are then connected to the same phase connections on the xfmr where they then cancel out. Some related ideas here: DC compensated SE output transformer
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