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Old 7th October 2009, 10:57 AM   #1
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Default 10dB increase in volume needs what gain?

Right I can't work out for the life of me what mu I need to increase signal 10dB, is it x10 or my other calculation of 3333.3 using two stages? It's for a feedback relay
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Old 7th October 2009, 11:04 AM   #2
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Gain in dB's = log(A)*20 where A is the gain

Gain from dB' = 10^(dB/20) (10 powered to dB/20)

10 dB gain is 10^(10/20) = 3.1

Check also wikipedia for dB calculations.
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Old 7th October 2009, 11:13 AM   #3
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I'm assuming you mean a x10 increase in volume means sound pressure level?

In which case the correct formula are:

10log(Pout/Pin) for power giving 3dBm increase for a doubled sound pressure level or 10dBm for a ten fold increase.

Translating that to a voltage gain into a load to achieve that sound pressure level gain you use:

20log(Vout/Vin) giving 6dB increase for a doubling of voltage and 20dB for a ten-fold increase.
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Old 7th October 2009, 08:54 PM   #4
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Here's the quick and dirty way to determine dB:

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