10dB increase in volume needs what gain?

Test Electrix · 7th October 2009, 10:57 AM

Right I can't work out for the life of me what mu I need to increase signal 10dB, is it x10 or my other calculation of 3333.3 using two stages? It's for a feedback relay

peranders · 7th October 2009, 11:04 AM

Gain in dB's = log(A)*20 where A is the gain

Gain from dB' = 10^(dB/20) (10 powered to dB/20)

10 dB gain is 10^(10/20) = 3.1

Check also wikipedia for dB calculations.

stratospheric · 7th October 2009, 11:13 AM

I'm assuming you mean a x10 increase in volume means sound pressure level?

In which case the correct formula are:

10log(Pout/Pin) for power giving 3dBm increase for a doubled sound pressure level or 10dBm for a ten fold increase.

Translating that to a voltage gain into a load to achieve that sound pressure level gain you use:

20log(Vout/Vin) giving 6dB increase for a doubling of voltage and 20dB for a ten-fold increase.

Palustris · 7th October 2009, 08:54 PM

Here's the quick and dirty way to determine dB:

http://www.sengpielaudio.com/calculator-db.htm

7th October 2009, 10:57 AM	#1
Test Electrix diyAudio Member Join Date: Mar 2009	10dB increase in volume needs what gain? Right I can't work out for the life of me what mu I need to increase signal 10dB, is it x10 or my other calculation of 3333.3 using two stages? It's for a feedback relay

7th October 2009, 11:04 AM	#2
peranders Electrons are yellow and more is better! diyAudio Member Join Date: Apr 2002 Location: Göteborg, Sweden Blog Entries: 4	Gain in dB's = log(A)*20 where A is the gain Gain from dB' = 10^(dB/20) (10 powered to dB/20) 10 dB gain is 10^(10/20) = 3.1 Check also wikipedia for dB calculations. __________________ /Per-Anders (my first name) or P-A as my friends call me

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7th October 2009, 11:13 AM	#3
stratospheric diyAudio Member Join Date: Oct 2009	I'm assuming you mean a x10 increase in volume means sound pressure level? In which case the correct formula are: 10log(Pout/Pin) for power giving 3dBm increase for a doubled sound pressure level or 10dBm for a ten fold increase. Translating that to a voltage gain into a load to achieve that sound pressure level gain you use: 20log(Vout/Vin) giving 6dB increase for a doubling of voltage and 20dB for a ten-fold increase.

7th October 2009, 08:54 PM	#4
Palustris diyAudio Member Join Date: Aug 2006 Location: Cape Cod	Here's the quick and dirty way to determine dB: http://www.sengpielaudio.com/calculator-db.htm

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