Lets do the math first.
So what do we know now? You have 165 volts over a 30 k resistor that ties B+ and ground together. Thats the simulated audio circuit.
Ohms law says U=R*I or the other way I=U/R
165 Volts divided by 30 000 ohms is 5,5 mA
We can check this over the 20 k filter resistor also since all current passes that one also.
109 volts divided by 20 000 ohms is 5,45 mA.
If you should now plug in a tube, biased at 5,5 mA (bias is controlled by the resistor between cathode and ground in the relation to B+) you should now have 165 Volts B+.
Are you with me on that? Shall we try?
So what do we know now? You have 165 volts over a 30 k resistor that ties B+ and ground together. Thats the simulated audio circuit.
Ohms law says U=R*I or the other way I=U/R
165 Volts divided by 30 000 ohms is 5,5 mA
We can check this over the 20 k filter resistor also since all current passes that one also.
109 volts divided by 20 000 ohms is 5,45 mA.
If you should now plug in a tube, biased at 5,5 mA (bias is controlled by the resistor between cathode and ground in the relation to B+) you should now have 165 Volts B+.
Are you with me on that? Shall we try?
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