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#1 |
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diyAudio Member
Join Date: Jan 2009
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Ok,
I have searched the forum and found very little definitive info on this subject. Here is my quandry I am designing a PP output stage using 2 x 829B's. They will be Triode strapped and paralleled. (don't ask why these tubes..I just like a challenge) I am having a tough time calculating the Miller Cap of these tubes. It gets complicated because a: the two sections are parallel and B: its a pentode "triode strapped" Inter-element caps are as follows per section Cgk 14.5 Cak 7 Cga 0.12 Stage gain will be about 8-9 maybe. I realize that some of these values will double due to the parallel connection but can someone help me with the method of calculating it? I need to know how low I need to get the output impedance of the driver stage to keep response up to 25Khz or so. |
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#2 |
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diyAudio Member
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Expect something in range 40-100 pF.
That means, for 50 KHz pole you need at least 30 kOhm. |
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#3 |
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diyAudio Member
Join Date: Jul 2003
Location: Ann Arbor, MI
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hey-Hey!!!,
There is also the internal g2-k capacitor. As triodes, this now becomes part of the plate circuit. cheers, Douglas
__________________
the Tnuctipun will return |
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#4 |
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diyAudio Member
Join Date: Jul 2004
Location: Ardeche
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Those tubes sometimes integrate an internal bypas capacitor btwn screen and cathode.
Near 200pF IIRC. But it appears accros the load, not as a "Miller multiplier" ! Yves. |
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#5 |
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diyAudio Member
Join Date: Jul 2004
Location: Ardeche
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Slower !
Douglas wins ! |
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#6 |
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diyAudio Member
Join Date: Jan 2009
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Thanks for the replies but I still don't have a definitive answer.
What is the formula for this type of calc? |
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#7 | |
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diyAudio Member
Join Date: May 2006
Location: York
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Quote:
Cin = Cgk + [(Cg1a+ Cg1g2) * gain] The problem is in finding a datasheet which gives you a genuine value for Cg1a. Cg1g2 may also be hard to find, but is probably less important. |
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#8 | |
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diyAudio Member
Join Date: Jul 2003
Location: Ann Arbor, MI
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Quote:
cheers, Douglas
__________________
the Tnuctipun will return |
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#9 |
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diyAudio Member
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#10 |
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diyAudio Member
Join Date: Jan 2009
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Well the data I have been able to find is as follows
Cgk = 14.5 (also listed as input C) so I am assuming Grid 1 to cathode Cak = 7 (internal capacitance of plate to cathode) Cga = 0.12 grid to plate I found spec that shows the capacitance of G2 to Cathode including the capacitor is approximately 65pf G3 is tied to the cathode. So, with these numbers what do I do? G2 tied to the plate and is part of the load so where does the 65pf fit in? Ignored correct? Cak also load it is ignored also? Do I ignore the G1 to G2 capacitance or make one up? so if I take the Cga and double it (for parallel) and multiply by 10 (gain 9 +1) I get 24pf Then add twice the Cgk = 29pf I get 53pf?? |
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