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#1 |
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diyAudio Member
Join Date: Aug 2006
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After looking at some RCRC networks, I wonder how the resistors used don't burn up. For example :
http://diyaudioprojects.com/Tubes/KT...Pull-Tube-Amp/ Scroll down and look at the PS resistor , a 100 ohm 5W unit. How is this NOT burning to a crisp ? It is providing ALL the power for a pair of Class A KT88's ! Thats gotta be close to 50W combined on the plates . Can someone enlighten me , PLEASE ? As long as we're looking at this schematic, what is the benefit of loading the V2 tubes' screen with a resistor rather than directly tying it to ground as per the Melvin Lebowitz original design ? Thank you................................Blake |
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#2 |
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diyAudio Member
Join Date: Dec 2002
Location: Calgary, Alberta
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P=I^2 * R
For 100 mA, R=100, P=1W For 200 mA, R=100, P=4W The screen of V2 is not tied to ground, the grid is. The tube is drawn upside down.
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Aerodynamics are for people who can't build engines. Enzo Ferrari |
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#3 |
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diyAudio Member
Join Date: Aug 2006
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"The screen of V2 is not tied to ground, the grid is."
My fault. Any idea why he used a resistor inline there ? "P=I^2 * R For 100 mA, R=100, P=1W For 200 mA, R=100, P=4W" Never saw that formula before. Sweet shortcut ! Thanks...................Blake |
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#4 |
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diyAudio Member
Join Date: Dec 2002
Location: Calgary, Alberta
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The design uses grid stopper resistors, while the one in the original article does not.
__________________
Aerodynamics are for people who can't build engines. Enzo Ferrari |
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#5 |
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diyAudio Member
Join Date: Aug 2006
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"The design uses grid stopper resistors, while the one in the original article does not. "
Yeah, I noticed that it is different than the original. I was wondering WHY he did it. I thought a grid stopper went from the grid to ground , not in series with the grid. ..................Blake |
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#6 | |
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diyAudio Member
Join Date: Oct 2003
Location: Sydney
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Quote:
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#7 |
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diyAudio Member
Join Date: Aug 2006
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Nobody likes a smarta** .
P=I^2 *R is NOT Ohms Law. It's not even Thevenin's Power Law. Ohms law is V/I=R or I * R = V or V/R=I . Amps squared , multiplied by Resistance equals Power is not taught in ANY school or books that I know of. How did you come to know it ? Any takers on the Grid Stopper question? A series resistance inline with the grid constitutes a grid stopper ? As I already said, I thought a parallel resistance from the grid to ground was considered a grid stopper. Can anyone clarify ? .................Blake |
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#8 | |
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diyAudio Member
Join Date: Nov 2006
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Quote:
Going back to the resistor / power question; remember that it is the power dissipated in the component / device that is to be considered and it is not going to be the same as that dissipated in the target load. Power = Current x Voltage Power = Voltage(squared) / Resistance Power = Current(squared) x Resistance The amount of power a component can take varies with ambient temperature (and sometimes with physical orientation). Always choose a component that can handle higher power than the calculated figure. For example if you calculate a dissipation of 0.8W in a resistor it would be wise to choose a 2W resistor. |
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#9 | ||||
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diyAudio Member
Join Date: May 2005
Location: Stittsville, Ontario, Canada
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Quote:
Quote:
used to drain away charge from the grid. Quote:
Quote:
P = I * V V = I * R P = I * I * R
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Robert McLean |
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#10 |
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diyAudio Member
Join Date: Aug 2006
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Thanks for the info. I had "Basic Electricity" (a 1 hour a day course) and "Electronics" ( a 2 hour a day course) in high school , and the variants of the power law using the square of voltage or current were never taught.
I never thought my teacher really knew what he was doing. That was some time ago, about 15 years, but seriously this is the first time I have seen it used this way. Thank you. Here's a schematic of my current setup. Do I need stoppers or "leak" resistors ? I plan on using CCS later. http://img353.imageshack.us/img353/1...rrentsetup.png .......................................Blake |
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