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Old 12th July 2009, 12:52 AM   #1
nhuwar is offline nhuwar  United States
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Default Filters

Hi Guys,


Is there a formula for finding the ripple out of a choke input filter?

If there is can someone tell me it?


Thanks a mill,


Nick
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Old 12th July 2009, 01:23 AM   #2
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Yes there is, but it is mathematically rigorous and requires several stages of computation, not to mention a little education in filter theory.  I don't do it that way any more; I just plug my proposed filter into PSUD2, which has this math built into it, and let it tell me the answer.

http://www.duncanamps.com/psud2/index.html

It's free.

Thank you, Ben,

Poinz
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Old 12th July 2009, 01:35 AM   #3
nhuwar is offline nhuwar  United States
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Ya I know unfortunately I'm on my mac and my pc is down stairs.


Also psud2 can't handle a power supply running 6500 vdc at 2.5 amps.



You see my quandary LOL.



And no it's not for an audio amp, college design project.



Nick
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Old 12th July 2009, 01:54 AM   #4
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It's not to hard to model power supplies in LTspice. Someone ran it on their Mac using a piece of software called Crossover?

http://www.evilmadscientist.com/article.php/crossover
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Old 12th July 2009, 02:09 AM   #5
nhuwar is offline nhuwar  United States
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The programs are called parallels and fusion. I'm familiar with them just haven't bought one yet.

Oh yes I see the one called crossover too. Still haven't spent the money yet LOL.

Nick
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Old 12th July 2009, 02:37 AM   #6
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OK, here's an oversimplified method: Assume you're starting with 100% ripple at 120 Hz. You have a voltage divider - choke reactance and capacitor reactance. So let's say you have 3 Henries (2.26K @ 120 Hz) into 16 uF (83 Ohms). That's 27:1 so you're down to about 3.3% p-p ripple.

But PSU designer has no problem with 6500V and 2.5A - and it says about 5% ripple.
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Old 12th July 2009, 02:56 AM   #7
nhuwar is offline nhuwar  United States
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I didn't think you had a choice of a rectifier that went to that high a voltage.

I will play around with it tomorrow.

But thanks for the info Tom.


Nick
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Old 12th July 2009, 02:59 AM   #8
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You get a warning, but you also get a result. Simulated diodes don't smell quite as bad if you overvoltage them...
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Old 12th July 2009, 02:35 PM   #9
nhuwar is offline nhuwar  United States
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Thats pretty funny.

Oh one other question. For you estimate you did, how did you get 3.3 % from 27:1?


I did the same thing with the components I'm going to use and got 34.2 to 1. Would it be 2.9%?


Thanks,
Nick
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Old 12th July 2009, 04:16 PM   #10
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Quote:
Originally posted by nhuwar
Thats pretty funny.

Oh one other question. For you estimate you did, how did you get 3.3 % from 27:1?


I did the same thing with the components I'm going to use and got 34.2 to 1. Would it be 2.9%?


Thanks,
Nick

Excuse the mental arithmetic - 1/27 is 3.7%. Still more precision than it deserves, though, as it's a very rough approximation, ignoring loading.
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