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#1 | |
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diyAudio Moderator Emeritus
Join Date: Jan 2004
Location: Jakarta
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Quote:
* 1/2 6SL7 with CCS load; * 6AU6-6SL7 LTP splitter with cascode BJT CCS in the tail; * 6SN7 cf drivers; *EL34 pentode-mode PP outputs, into 3.5k p-p load; * Global NFB (with the usual compensation to prevent LF and HF instability). It models very well, showing good balance and low distortion - much lower than I can get with the usual Mullard-type circuit using a conventional double triode splittter or with a dual pentode splitter. I realize it's only a model, but . . . |
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#2 |
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diyAudio Member
Join Date: Jul 2005
Location: Leverkusen
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Hi Ray_Moth,
there is an article from Mr. A.R. Bailey himself about this interesting Schmitt type inverter: A New Phase-Splitter, A.-R. Bailey, Wireless World, September 1962. Probably Mr. Bailey designed this circuit for Radford and/or even worked for them for some time. Also, there is a French language article summarizing it: Un Inverseur de Phase Amélioré, Revue du Son. Both articles definitely can be found as scans somewhere on the ´Net. Some time ago I wrote some sort of analysis of those typical Radford PP amp frontend/splitter-combos from Mr. Bailey myself, which can be found here at Jogis Röhrenbude (German language). The full "beauty" of this circuit is only revealed in the amp context, working together w/ the input stage in front of it and power stage after it. Just picking this dissimilar tube section Schmitt inverter out of its context doesn´t make much sense, I think, because when viewed as a "standalone splitter module" alone, it isn´t much appealing ... Regards, Tom Schlangen EDIT: P.S.: You wanting to improve it by putting a CCS in the fully intentional very short "long tail" (actually, this is not an LTP whatsoever), clearly shows you didn´t understand how it really works
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If in doubt, just measure. |
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#3 |
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diyAudio Member
Join Date: Nov 2007
Location: Dallas
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Looks completely familiar to me. Its cathode coupled anti-triode.
Tail wagging the dog. By that, I mean driving from the Anti-side. Whichever device has the overwhelmingly Higher Gm becomes the Anti-complement of the weaker Gm device. A transparent flavorless inverter of the weaker device's single endedness. Or you can look at it as a cascode, bent into a U shape. CCS tail not strictly necessary, but it won't hurt anything. |
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#4 | |
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diyAudio Member
Join Date: Jul 2005
Location: Leverkusen
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Hi kenpeter,
Quote:
Hint: Have a close look at the ECF82 pentode screen grid feed and its AC clamping, then think about what changing smallish R13 (see below) to a CCS will do: - to the stage gain of the ECF82 pentode section - to the distortion of the ECF82 pentode section - to the output impedance of the ECF82 pentode section Think local cathode FB for the pentode section - we don´t want to lose its merits, eh Redrawn circuit for convenience see below . Regards, Tom Schlangen EDIT: Uh, oh, the linked circuit picture suddenly got replaced by a "deeplink" sign. I attached it as a file again below. Hey moderators, I have drawn this schematic myself!
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If in doubt, just measure. |
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#5 |
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diyAudio Member
Join Date: Aug 2008
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I agree that technically it is not a true LTP and I thank you for your post; it has certainly made me re-think if it is worth tampering with the cathode circuit by using a CCS. I note that the later Radford STA25’s [made by John Widgery] used the same phase-splitter but had the anode resistors connected to a potentiometer with the wiper connected to HT to adjust balance. Also the pentode screen voltage was clamped by a zener diode.
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#6 |
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diyAudio Member
Join Date: Nov 2007
Location: Dallas
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CCS works. R14 and R9 merely have to be the same value.
As with a Cathodyne, even if drive signals are identical and opposite into exactly equal loads. The plate impedances are not equal and won't react similarly if the loads misbehave. Unless there is something in the Radford that fixes this, and I'm missing it. -------------------------------------------- You don't "need" resistive feedback under the Pentode for the Pentode to be linear. You have Triode feedback. You merely need it to be a strong follower of the input. Mu of Triode V2A and R14 will decide the current that reflects back through the Pentode into R9. And assuming both plate resistors driving identical loads, it works at least as good as a Cathodyne. But with gain. Matters not the small detail of V2B screen bypassed to ground rather than cathode. As the functions of V2B as strong cathode follower and top half of a U bent Casocode, are not where the current control happens. With CCS in the tail, That decision is for V2A and R14. -------------------------------------------- It might help to understand why Radford favored a small resistor tail, if we had a full translation? All I got to go on for now, is your schematic. |
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#7 |
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diyAudio Member
Join Date: Dec 2001
Location: Hickory, NC
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I think the reason R13 is at 8.2K here, is for a not so common mode feedback loop back to the EF86 plate thru R6. Everything is DC coupled between these tubes. The ECF82 triode has a higher gm than the pentode, so AC signal causes net current variation to develop an AC voltage across R15, which feeds back to V1 via R6. A CCS would spoil this DC biasing feedback loop.
If it weren't for this DC loop, I would put a CCS in. More linear. For possible improvements, I would try a small Mosfet of Depl. FET (LND150) to operate the ECF82 screen grid. Source to screen, gate to Vref, and drain to the pentode's plate. That way th e screen current gets put back into the plate output as if purely triode. Don For possible improvements, I would try a small Mosfet of Depl. FET (LND150) to operate the ECF82 screen grid. Source to screen, gate to Vref, and drain to the pentode's plate. That way the screen current gets put back into the plate output as if purely triode. (This only works if the dynamic plate voltage stays above the screen voltage though.)
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Ohms Law V = I R |
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#8 |
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diyAudio Member
Join Date: Nov 2007
Location: Dallas
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If the triode has the higher Gm, thats a whole different animal.
It becomes an anti-pentode and the "top half" of the U, and Mu won't apply in a Gm limited (to that of the weaker pentode) situation. I guess current control must come from somewhere else than the Triode for this to work. I'm not buying any loop feedbak thru R6 to the EF86 plate. As you are ignoring the bypass effect of C3. |
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#9 |
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diyAudio Member
Join Date: Dec 2001
Location: Hickory, NC
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C3:
It's a DC bias servo loop for the ECF82, C3 is OK. The triode section of the ECF82 is still providing plate Mu feedback to the splitter here, a dual pentode splitter would be operating open loop. So looks like the pentode side gets rid of Mr. Miller, and the triode side keeps things linear. Don
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Ohms Law V = I R |
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#10 |
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diyAudio Moderator
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With a CCS, wouldn't you want to attach the screen's AC bypass to the cathode instead of ground?
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