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#1 |
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diyAudio Member
Join Date: Aug 2006
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Looking to buy a "plug-in" tube bias tester. Any brands you are familiar with or can recommend ?
It seems most brands on Ebay measure the cathode current. Is this equivalent to measuring the Plate/Anode current ? Seems as though it should be pretty close. http://cgi.ebay.com/AMP-HEAD-Bias-Te...3A1%7C294%3A50 Thanks for your input. ..................Blake |
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#2 |
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diyAudio Moderator
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Cathode current is plate plus screen current. That's dominated by plate and you can use it to a good approximation. However... all it is is a 1R resistor. You could just solder one in permanently (though most amps already have a current sensing resistor) and save $28.85.
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“Listening to records is like ****ing a picture of Brigitte Bardot.” - Sergiu Celibidache |
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#3 |
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diyAudio Member
Join Date: Aug 2004
Location: Mansfield, Connecticut
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This brings up a question I have about these adaptors.
I just built one of these myself, and I'm going to add the 1R resistor externally instead of having it inside the adapter. My question is, these types of bias measuring devices can't really be used on SE amps, can they? The reason I ask is that typically the SE amps I have run high wattage power resistors as the cathode bias resistor (10-25w). They don't make 10W 1R 1% power resistors, do they? I'm afraid that I'll cook the 1R resistor on the adapter if I just use an average 1/2W resistor. Any suggestions? Sorry for the hijack, but this question is kind of relevant. Glenn
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"Imagination is more important than knowledge" |
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#4 |
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diyAudio Moderator
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You don't need high power for that resistor. Suppose that your tube is run at 100mA (which is pretty stout). The wattage dissipated in a 1R is P = I2R = (.01)(1) = 10mW. The resistor doesn't care if it's a push pull or single ended amp.
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“Listening to records is like ****ing a picture of Brigitte Bardot.” - Sergiu Celibidache |
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#5 |
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diyAudio Member
Join Date: Nov 2004
Location: Midwest Madman
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#6 |
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diyAudio Member
Join Date: Aug 2006
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If it is just as simple as measurig the voltage from the Cathode through a precision 1 0hm resistor, and the Mv=Ma , then couldn't I do that to the Plate and get a more accurate reading (no screen draw ) ?
Thanks for the info ! .......................Blake |
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#8 | |
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diyAudio Moderator
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Quote:
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“Listening to records is like ****ing a picture of Brigitte Bardot.” - Sergiu Celibidache |
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#9 |
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diyAudio Member
Join Date: Aug 2006
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Ok,
So I'll need to hook up one end of the resistor to the cathode , and the other end floats ? Attach one lead of the VM to each side of the 1 ohm resistor , and Mv=Ma ? I am running only 1 cathode bias resistor for both tubes, so I would need to divide the Mv/Ma# by two , right ? Then subtract the cathode bias voltage from the Anode voltage, take that # and multiply it by the Ma's to get total power for the Anode ? Anode V= 405V Cathode Bias V= -30V Actual V= 375V Ma's/2 x 375V= Total Power across Anode I am running my output tubes with a single cathode bias resistor without a bypass capacitor (differentially). As far as I understand it, I need to run the outputs in Class A for this to work properly. I am planning on running them at about 90% of rated Anode power. Is this the correct way to go, or should I run them at a higher or lower percent ? .................................Blake |
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#10 |
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diyAudio Moderator
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No, the resistor goes from cathode to ground. The measure the voltage between the cathode end and ground and you're good to go. An ohm will have hardly any effect on the operation of the stage so don't worry too much about running AB.
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“Listening to records is like ****ing a picture of Brigitte Bardot.” - Sergiu Celibidache |
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