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#1 |
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diyAudio Member
Join Date: Aug 2006
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#2 |
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diyAudio Moderator Emeritus
Join Date: Oct 2007
Location: Santa Cruz, California
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D3 is in parallel with D5, D6 in parallel with D1. The full secondary voltage is presented to B+1 and ground through the bridge. Your B- will be at best, 0V.
Sorry, this won't work.
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#3 |
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diyAudio Member
Join Date: Aug 2006
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#4 |
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diyAudio Moderator
Join Date: May 2003
Location: Palatiw, Pasig City
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no....won't work...sorry, you B- will still be 0....
__________________
http://www.elab.ph/forum/index.php?topic=32688.0 |
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#5 |
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diyAudio Moderator Emeritus
Join Date: Oct 2007
Location: Santa Cruz, California
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Yes, that performs equally well for less cost
Your only options are: A: to split the bridge output using resistors (as you are doing for B+1 and B+2) Then the bridge output provides B+1 and B-, you use resistors to create 0V and B+2. This is messy, wastes power and creates soggy(high impedance) rails. B: use some kind of switched mode PSU to create the -ve additional rail from the B+1 rail. If B+1 is high voltage then this is ugly. C: get a proper transformer. Sorry, but a single winding really only produces a single rail. There's no free lunch even when you DIY
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#6 |
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diyAudio Member
Join Date: Aug 2006
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#7 |
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diyAudio Member
Join Date: Jun 2004
Location: Pittsburgh, crumbling wasteland
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#8 | |
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diyAudio Member
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Quote:
I was just going to suggest that little trick.
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#9 |
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diyAudio Member
Join Date: Jun 2002
Location: Macedon NY
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How much B- current do you need? You may be able to use a half-wave rectifier capacitor coupled to one end of the winding.
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#10 |
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diyAudio Member
Join Date: Aug 2006
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Interesting article on back-biasing, but I unless I'm missing something this won't work in this case since my secondary winding has no center tap.
Tom, current will not exceed 10 ma. Is that within reason for what you're suggesting? |
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