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#1 |
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diyAudio Member
Join Date: Oct 2003
Location: lower Austria
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Hi,
I recently received an custom built (DIY) all-tube pre-amp. The line-stage works just GREAT but the phono-stage is not so good at all. It sounds to low, no dynamics and as if the tweeter was not working at all. Something is wrong and I suspect the design of the schematics to be off (wrong Cap/resistor vlaues probably?). Problem is, the person who built it cannot hear it as I do and could not fix it either. Would anybody here be willing to run the schematics (which I have in PDF format) through spice or tubecad or whatever tool available, to check if all the parts values calculate correctly? This would be of tremendous help to me. The schematics is very similar to the pre-amp described in the book "hoechst empfindlich" of Goetz Wilimzig. 2 E88CC in the phono-stage and 1 E280F (Triode mode) in the line-stage, with passive RIAA EQ. I am an illiterate when it comes to electronics-design but like to build things. So I could try to fix it once somebody who knows better has determined the correct values or found a theorethic error. Many thanks in advance for any help offered! Dieter |
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#2 |
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diyAudio Member
Join Date: Aug 2002
Location: Sofia
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Let me ask the obvious question: what is your cartridge and what is the loading impedance of the preamp? If you load a MM cart with a very low resistance suitable for MC you may experience some very dull sound. Of course it's best to post the circuit.
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#3 |
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diyAudio Member
Join Date: Oct 2003
Location: lower Austria
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Hi,
It is not a cartridge impedance problem. I tried various MM & MC/Step-Up set-up and compared the results to other (OP-Amp & Tube) phono stages. This baby always came out way last. But for the record: I tried a Shure MM with 90K load & 47K load. I tried various capacities with NO impact on the sound quality of this Pre. Same (bad) results with a clearaudio Stradivari (MC) via a Silvercore 1:10 100K Step-Up which usually sounds marvelous, using 47K, 90K and NO load at the phono-input. cheers, Dieter |
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#4 | |
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diyAudio Member
Join Date: Aug 2002
Location: Sofia
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Quote:
Hi Dieter Sorry for the trivial question, i didn't realise you were a seasoned vinyl-phile ![]() A circuit seems essential then. Any idea what "NO load" means? There is obviously a resistor at the first tube's grid which determines the maximum value of the input resistance. I assume you change resistors in parallel to this internal resistor to set your desired value. The difference between 90k and 47k is usually quite subtle; what i had in mind was loading a MM cart (or the secondary of a transformer) with a 100ohms. |
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#5 | |
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diyAudio Member
Join Date: Dec 2003
Location: San Diego
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Quote:
Sheldon |
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#6 |
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diyAudio Member
Join Date: Oct 2003
Location: lower Austria
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I just now realized I could upload as well
. I hope this will suffice for anybody willing to do the math on the RIAA inverson:There's one small error: the last resistor, connecting the Output to ground (2,2Meg) is missing on the circuit diagram. The values are as published in the book. Actual, if different, values are provided in brackets. Major differences to the official version are marked in red. The descriptions are in German: müF --> uF U1/U2 --> V1/V2 fehlt im Original --> does not exist in original schematics BR Dieter |
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#7 |
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diyAudio Member
Join Date: Mar 2004
Location: Budapest, Hungary
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The capacitors are 10x as large than they should be.
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#8 |
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diyAudio Member
Join Date: Oct 2003
Location: lower Austria
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... there's another issue which I did not mention earlier:
I'd be very happy if next to the filtering the gain could be improved as well. I think two 6922 should be able to amplify a MM Cartridge to the same level like a Tuner or CD Player, which is not the case currently. D |
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#9 |
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diyAudio Member
Join Date: Oct 2003
Location: lower Austria
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@oshifis
not meaning to be rude , but could you please be more precise?thx Dieter |
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#10 |
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diyAudio Member
Join Date: Mar 2004
Location: Budapest, Hungary
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Sorry, I wrote it in a hurry. I refer to the paper of Stanley P. Lipschitz titled "On RIAA Equalization Networks" (J.A.E.S. 1979 June). See section 8 Addendum where he describes the formula for passive eq networks. The relevant formulas are:
R1 * C1 = 2187 us R2 * C2 = 109.05 us R1 * C2 = 750 us R2 * C1 = 318 us R1 / R2 = 6.877 C1 / C2 = 2.916 R2 is R3 on your diagram, C1 is C4 and C2 is C5. C4 = 3.0 nF and C5 = 1.0 nF give quite good values. The plate resistance ( cca. 16k according to my calculation) adds to R1. |
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