|
|
|||||||
| Home | Forums | Rules | Articles | Store | Gallery | Blogs | Register | Donations | FAQ | Calendar | Search | Today's Posts | Mark Forums Read | Search |
| Tubes / Valves All about our sweet vacuum tubes :) Threads about Musical Instrument Amps of all kinds should be in the Instruments & Amps forum |
| diyAudio Sponsor | ||
|
|
||
|
|
Thread Tools | Search this Thread |
|
|
#1 |
|
diyAudio Member
Join Date: Jul 2007
|
I've just rebuilt a little McGohan M102 PA head. The idea is that it will be used to drive the reverb send in my home studio (the reverb "chamber" is my hardwood-floored living room).
So rather than taking a balanced mic-level or unbalanced phono input (both of which it's set up to do), I'll be taking a balanced line-level signal out of my DAW and running it through the amp. I'm assuming that all I need is an input transformer rated at 600 ohms primary to 50k ohms secondary to drive a 6AU6A (the first preamp tube). However, studying the schematic more closely, it might make more sense to skip the first gain stage and route the transformer output to the phono stage. After all, I'll be using a +10dbm signal, and I doubt I'll need that much gain. The physical rerouting of the signal is easy; what I'd like to know is what the second gain stage (a 6EU7) wants to see in terms of impedance. I've searched for a reference for "typical" values but have come up short. Is there a guidebook, or at least a rule of thumb? Many thanks, Seth ![]() McGohan M102 Schematic |
|
|
|
|
#2 | |
|
diyAudio Member
|
Quote:
|
|
|
|
|
|
#3 |
|
diyAudio Member
Join Date: Jul 2007
|
Hmmm....interesting. After bouncing between the schematic and the RCA tube book for the last 30 minutes, I was beginning to think the same thing: It's dependant on the grid resistor.
"DAW"? That's Digital Audio Workstation, I believe, a fancy term for "my computer." The computer will be putting out standard line level: +10db at 600ohms. That's not the issue; what I'm trying to figure out is what the secondary of the input transformer should be. For what it's worth, the unit came with a 150ohm/50kohm mic transformer. I would use it, but 150 sounds pretty far away from the 600 the computer is putting out. If the line transformer is putting out 50kohms, does that mean I should change the grid resistor of the phono stage 6EU7 (currently 330K) to something closer to 50K? -Seth |
|
|
|
|
#4 | |
|
diyAudio Member
Join Date: Jan 2005
Location: South Florida
|
Quote:
-- josé k. |
|
|
|
|
|
#5 |
|
diyAudio Member
Join Date: Jul 2007
|
Thanks much for the replies, gents. Unfortunately, I'm still scratching my head. Specifically:
-Miles, if the input impedance were essentially the same as the grid resistor, why is there no input resistor on the first gain stage (the 6AU6A)? (I see a 1 meg grid-to-ground resistor, but that's different, right?). -Jose, thanks for the tip; I have a couple of 150/600 primary transformers...I'm more concerned with the secondary and how it interacts with the tube. The unit I'm working on came with a mic input transformer rated at 150/50K (I have a similar one labeled "line input transformer" rated at 600/15K). Why would I use one (15K) or the other (50K)? Thanks much, Seth |
|
|
|
|
#6 | |
|
diyAudio Member
|
Quote:
|
|
|
|
|
|
#7 |
|
diyAudio Member
Join Date: Jul 2007
|
Thanks Miles! But wait...still mightily confused over here. What's the relationship between the output of the transformer (50K) and the input resistance of the tube (1 meg)? And "hollow state"? "BJT"?
If I'm reading you right, you're essentially saying: "Use whichever transformer you like, unless it has a huge (>100kohm) impedance.... Help. -Seth |
|
|
|
|
#8 | ||
|
diyAudio Member
|
Quote:
Vsec / Vpri= sqrt(Zsec / Zpri) so: Vsec / Vpri= sqrt(50E3 / 150)= 1 : 18.26 So this xfmr has a voltage step up ratio. As for impedance, then, yes, a secondary load of 50K will appear as an equivalent source resistance of 150R. As for how this relates to the 6AU6, the total impedance at the grid becomes: Rg || Zsec, which would be approximately 47.6K. As for other impedances, these will be transformed by the same impedance ratio of 1 : 333. As for which one to use, go for the 600 : 15K. The voltage ratio is lower, and you already have a ton of gain there. Also, the lower the impedance seen at the input side, the harder that load becomes to drive. I'd give it a secondary load of 100K or so and see how that works out concerning frequency response and ringing. As for myself, I have an iron allergy. I try to avoid chokes and xfmrs as much as possible. There will be those who disagree, but that's my design philosophy. Quote:
BJT: Bipolar Junction Transistor. |
||
|
|
| Currently Active Users Viewing This Thread: 1 (0 members and 1 guests) | |
| Thread Tools | Search this Thread |
|
|
|
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Simple SE, how to wire CFB with outputs for different speaker impedances? | ciagon | Tubes / Valves | 1 | 28th August 2008 12:35 PM |
| Op-amp input impedances and a pot/attenuator | breez | Chip Amps | 5 | 1st February 2005 01:17 PM |
| Input transformers and IC input impedances | duffy | Chip Amps | 4 | 2nd December 2004 06:08 AM |
| line input impedances? | Dominique | Parts | 5 | 5th August 2004 11:19 AM |
| How does a summing circuit work in terms of input/output impedances? | Saurav | Everything Else | 3 | 16th May 2003 04:10 PM |
| New To Site? | Need Help? |
| Page generated in 0.12869 seconds (79.66% PHP - 20.34% MySQL) with 10 queries |