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#1 |
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diyAudio Member
Join Date: Nov 2001
Location: Trondheim
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Hello!
I have found a powersupply choke from an old radio. With my multimeter i measured the inductance to be 28H, with a DC winding resistance at 716 ohms. Now, I want to use this one, but I have no clue on the maximum current it can handle before saturating. The core size is the same as for a 10H at 50mA choke that I have... Is there any means as to determine the maximum current? Stigla |
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#2 |
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diyAudio Member
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the easiest answer is to guess from the output tubes which were in the old radio. It will get you in the ballpark.
this choke has very high DC resistance, so it will heat quickly, 716 R and 50ma = 1.79W from P = (I^2) * R |
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#3 |
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diyAudio Member
Join Date: Jul 2002
Location: New Zealand
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Don't destroy a nice old radio for parts!!! Buy the proper ones!!
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#4 | |
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diyAudio Member
Join Date: Nov 2001
Location: Trondheim
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Quote:
The output tube was a 7C5 (equal. to 6V6) with a handfull of other Loctal preamppentodes. It is hard to tell, but I suspect that the choke was not handling the anode current of the 7C5, but just the screen supply and the rest of the smaller penodes... The filter cap had obiously blown, leaving the usual electrolyte "guts" on most of the insides... That should suggest perhaps a current level no higer than perhaps 10mA? |
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#5 |
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diyAudio Member
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a.m. radio was never better than in the old consoles -- we had one in the ham radio shack in high school 30 years ago -- could listen anywhere within about 400 miles of the school during the day !
I suggest that a refinishing job on the cabinet might be in order. |
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#6 |
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diyAudio Member
Join Date: Oct 2002
Location: Brooklyn, NY
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400 miles? That's nothing
I've done 1,200 with a regenny.
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