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Old 17th March 2018, 09:31 AM   #1581
jan.didden is offline jan.didden  Europe
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Good point P-A. A good way to figure this out is to put the circuit in LTspice and ramp the input from 0 to max and look at the various nodes.

Jan
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Old 17th March 2018, 05:24 PM   #1582
hellokitty123 is offline hellokitty123
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Quote:
- You are not just talking to me. You are talking to members of this forum many of them do not know circuits as these by heart, but would be interested to follow this and/or offer insight. That's the nature of this forum. It's not a one-to-one affair.

- You may have made an error adapting a known circuit to your own use. This does happen, and we should always discuss the actual implementation that gives the problem.
Good point.
Quote:
My gut feeling is that you have not a full grip of what happens during start-up.
No certainly not. That's the big question.
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Old 15th May 2018, 08:59 PM   #1583
arivel is offline arivel  Italy
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Good morning to all and excuse my English.
I have some problems with the regulator and then I thought about asking here.
can you help me please? .
the questions are many, please be patient.

- I do not understand the following sentence:
"A word about the input voltage from your rectifier / reservoir caps: make sure it is at least 5V above the required output voltage."

- what does the following text mean? :
"And, do not put a high-quality film cap at the output of the regulator! 10 oF (and do not overdo it) at the end of the period.
Do I need to add a 10 μF capacitor between output and load?

- 0.25W resistors are often metallic film?

- between the diode rectifier bridge and inputs J1, J5 must I add a capacitor or are sufficient C2, C6?

- I need two positive and equal tensions for
feed the PCM1794 + 8V + 8V chip (can you do?) and two opposite voltages for the carlsor + 12V-12V buffer for DDDAC1794 and then I did the following calculations using the formulas from the Jan Didden web page.

x output + 12-12 volts:
R5, R12 = (12V - 6.9V = 5.1V) then 5.1V / 0.002mA = 2.55k ohms
D5, D10 = 6.9V LM329
D2, D7 = 6.2V
BZX79B6V2 R0G Taiwan Semiconductor | Mouser Italia
R13, R7 = 6.9V / 0.002mA = 3.45K ohms
V (R14, R6) 12V - 6.9V = 5.1V
R14, R6 = (5.1V / 6.9V) x 3.45K = 2.55K ohms

x output + 8 + 8 volts:
R5, R12 = (8V - 6.9V = 1.1V) then 1.1V / 0.002mA = 550 ohms
D5, D10 = 6.9V LM329
D2, D7 = 3.9V
BZX55C3V9 R0G Taiwan Semiconductor | Mouser Italia
R13, R7 = 6.9V / 0.002mA = 3.45K ohms
V (R14, R6) 8V - 6.9V = 1.1V
R14, R6 = (1,1V / 6,9V) x 3,45K = 550 ohms

I noticed from my calculations that R5, R12, R14, R6 are the same, but in the order table on the web page R14, R6 is twice the size of R5, R12.
Furthermore :
R13, R7 are greater than R14, R6 instead in the order table on the web page are the same.
Where did I go wrong ?

- I can not figure out how to make connections for remote sensing of J2, J6
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Old 17th May 2018, 05:02 AM   #1584
peranders is offline peranders  Sweden
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It's not suitable to have the LM329 as voltage reference for 8 volts out. The opamp inputs will be too near the supply voltage of it. You should have a voltage reference at 4-5 volts. LM431 will work good. I use it
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Old 17th May 2018, 09:07 AM   #1585
jan.didden is offline jan.didden  Europe
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Quote:
Originally Posted by arivel View Post
- I do not understand the following sentence:
"A word about the input voltage from your rectifier / reservoir caps: make sure it is at least 5V above the required output voltage."
I don't know how to make it more clear. You know what the rectifier output means? That is the input to the superreg.

Quote:
Originally Posted by arivel View Post

Do I need to add a 10 μF capacitor between output and load?
It is a DC supply. Do you think there will be a DC current from regulator to load if there is a cap between regulator to load? ;-)
The output cap goes from output to ground and is clearly shown on the schematics.

For my superreg, all important issues are addressed in the writeup accessible from the diyaudio store super reg page.

I am sure P-A has a similar writeup.

Jan
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Old 17th May 2018, 01:13 PM   #1586
peranders is offline peranders  Sweden
Electrons are yellow and more is better!
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When it comes to minimum input voltage it is dependent of the LED colour. Red, yellow and green LED will generate 2.0-2.5 V drop out voltage and using a blue or white LED will add up to 2 V. The minimum voltage is with the ripple included so under no circumstances under 2.5 V but for having a marginal 5 V or more is recommended.

A good side effect is that the LED is on when you have a stable output voltage.
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