I just need to know the volume needed to obtain an optimally flat response -in car- for a sealed enclosure. that means calculated with cabin gain. I have a protege wagon if cabin size can be taken into account.
I just googled average interior volume of a car and hit wikiepedia.
http://en.wikipedia.org/wiki/Vehicle_size_class
Scroll down to USA regulations, small station wagon says under 130, over 120.
Anyway. I have a mac and am too lazy to drag the pc laptop out of the closet and find some software for it.
Here are the specs on my sub. I will be feeding it 300 watts.
Here are the technical specs;
Dual 4 ohm
Revc = 7.8 Ohm
Fo = 22.6 Hz
Sd = 350.0 cm^2
Krm = 2.1538m Ohm
Erm = 1.085
Kxm = 193.204m H
Exm = 0.588
Vas = 71.3 Ltr
Cms = 409.87u M/N
Mmd = 129.248m Kg
Mms = 133.013 g
BL = 19.032 T.M
Qms = 3.290
Qes = 0.37
Qts = 0.333
No = 0.22%
SPLo = 85.36 dB
Thanks in advance!
I just googled average interior volume of a car and hit wikiepedia.
http://en.wikipedia.org/wiki/Vehicle_size_class
Scroll down to USA regulations, small station wagon says under 130, over 120.
Anyway. I have a mac and am too lazy to drag the pc laptop out of the closet and find some software for it.
Here are the specs on my sub. I will be feeding it 300 watts.
Here are the technical specs;
Dual 4 ohm
Revc = 7.8 Ohm
Fo = 22.6 Hz
Sd = 350.0 cm^2
Krm = 2.1538m Ohm
Erm = 1.085
Kxm = 193.204m H
Exm = 0.588
Vas = 71.3 Ltr
Cms = 409.87u M/N
Mmd = 129.248m Kg
Mms = 133.013 g
BL = 19.032 T.M
Qms = 3.290
Qes = 0.37
Qts = 0.333
No = 0.22%
SPLo = 85.36 dB
Thanks in advance!
Cabin gain is determined by the lengths of space inside the car, not volume. Give us the length and width of the internal cabin space and we can make a reasonable guess as to the cabin gain frequency.
Then you set F3 of the box to match this, with Qts dependent on sound preferences and length/width ratio of the cabin.
Then you set F3 of the box to match this, with Qts dependent on sound preferences and length/width ratio of the cabin.
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