need help reaching 140db in my house!!!!

[NEO Dan]

Originally Posted by geraldfryjr

You will need to displace 121,372 cubic centimeters of air to get 140db at 25hz.
And you will need 60,686 cubic centimeters of air for 140db at 35hz.
As well as 30,343 cubic centimeters of air for 140db at 50hz.

That should give you some idea of what it would take to reach such levels !!!

jer

Gee where do we start.... 30l at 50hz lets see - there are double 18" boxes that do 140dB and I'm sure the displacement is well under 2l. What about the Danley stuff that puts out ~150dB???

[imix500]

We just built 18 definite purpose boxes using 2x FaitalPro 18xl1500 at work. In a ~300L box with a single center vent and an f3 of 37Hz, we measured 146 @1M quarter loaded using pink with a lab fp3400 in bridged mode. That was at max output of the labgruppen and with headhoom to spare in the drivers. So, it's totally doable.

[geraldfryjr]

Well, If an 18" has a surface area of 254 with a excursion of 1" it would take 7.28 of them to do 50hz.

So 16 of them is about what I figured would get you to the 30hz range.

But that is at 1" excursion.

But if you concentrate the energy with a horn of some sort you may get some more gain out of them.

jer

[geraldfryjr]

Also don't forget the room gain.
the Dipole requirements I think were double that,
But 8 or 12 of them stacked up in dipole configuration per side just might do the trick !!!!

Insane,Ahhhhh,ha,ha,ha,ha,ha,ha !!!!!!!

jer

[kelticwizard]

Justin:

Here is the chart taken from Richard Small's article for volume displacement for SPL at various low frequencies:

[kelticwizard]

Now here is the same chart in inches, which I adapted from the original:

[kelticwizard]

The way it works is that the SPL at a given frequency goes up 12 dB when you quadruple the displacement.

Let's try for 30 Hz-we can always back off down to 40 Hz if we need to.

At 30 Hz, 128 cu in gives us 117 dB.

So, 512 cu in gives us 129 dB.

So, 2048 cu in gives 141 dB.

That means that, using closed boxes, we would need the cone area times the displacement to equal 2048 cu inches.

Assuming a one inch throw on a PA speaker, that means a cone area in a closed box of 2048 square inches. Considering a 15 inch speaker has a cone area of 130 sq inches or so, that means you would need about sixteen 15 inchers to achieve 140 dB @30 Hz.

[kelticwizard]

Assuming you don't want to do that, there are things you can do.

A. You can move your target frequency up to 40 Hz;

B. You can use ported enclosures, which change things in your favor.

Let's see what the displacement is for 140 dB at 40 Hz instead of 30 Hz. As we can see, 128 cu inches gives us 122 dB.

512 cu inches gives us 134 dB.

1024 cu inches gives us 140 dB. (Double the displacement = +6 dB).

Assuming a one inch travel on a PA speaker, that means 1024 sq inches, or about eight 15 inchers.

That is in a closed box.

However, if you use a vented box with a Qts of 0.38 or so, you can cut that displacement requirement by 4. Instead of a cone area of 1024 sq inches, (assuming a one inch throw on your PA speaker), you now need only one quarter as much, 256 sq inches. Since most 15's have a cone area around 130 sq inches, you should be able to get this done with two vented box 15 inch PA speakers, with a one inch throw, with a Qts around 0.38, a box volume equal to the speaker's Vas and tuned to 40 Hz or so.

[kelticwizard]

That takes care of the speaker volume requirments. The amp requirements are a different matter.

[salzburgsoundsystem]

we need a suitable design for Justin's 3015LF

If you can give him 140 dB @ 30Hz from a pair of them, I will be very impressed!

Regards, Ben