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#1 |
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diyAudio Member
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it seems there is very little that can be done to accuratly figure out how mych power a speaker can handle. and even if i can figure out how much it can handle it seems to change due to the type of music or duration etc. so what i would like to do is install a couple of wires directly to the aluminum former of the voice coil and hook up a guage for each sub.
can anyone off up any ideas on how to do something like this. if i can get any ideas i will just be using 2 wires soldered to the inside of the former and using my multimeter with e temp monitor to watch the temperature. i would think that a little readout or an actual gauge would work much better. |
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#2 |
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diyAudio Member
Join Date: Oct 2009
Location: Thurso, Quebec, Canada
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You can try and install a small thermocouple.
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#3 |
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diyAudio Member
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what is that? i was thinkinking of just running 2 wires?
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#4 |
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diyAudio Member
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You don't need a thermo couple. You can use the copper of the voice coil as is. Let me explain.. Copper has a positive thermal coefficient and increases in resistance as it gets hotter.
If one was to apply a constant bias current across the coil (ac coupled to the amp across a bank of capacitors), you could monitor the voltage change and apply a little math and viola! It doesn't matter what the current is, as long as it is measurable. If it's too high, you'll push the driver forward. A simple constant current source is a depletion mode mosfet like a DN2540 in a T0-220 package run source voltage at least the positive rail of the amplifier used. The math is this shown in Tcl from a test app I wrote. Code:
proc thermalCoef {T0 {material "cu"}} {
switch -- $material {
"cu" {set C 0.00385}
"al" {set C 0.00401}
}
return [expr {1.0/((1.0/$C)+($T0-25))}]
}
proc nowTemp {VT0 T0 VT1} {
return [expr {((1/[thermalCoef $T0])*(($VT1/$VT0)-1))+$T0}]
}
proc tempRise {VT0 T0 VT1} {
return [expr {[nowTemp $VT0 $T0 $VT1] - $T0}]
}
T0 = rest temperature VT1 = coil voltage to request temp for So basically, you start from a known temp and voltage, and read either the rise or absolute in Celsius. Be aware that you'll need some strong filtering if you use that with a sub. Maybe as much as an 8-pole bessel on the test signal and maybe as much as 20,000 uF for C1 depending upon your load.
__________________
Think out of the box
Last edited by davygrvy; 6th January 2010 at 02:19 AM. |
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#5 |
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diyAudio Member
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Here's a paper on the technique, but equation #7 can be simplified to use a constant current source as resistance is directly proportional to the voltage the current produces.
__________________
Think out of the box
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#6 |
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diyAudio Member
Join Date: Oct 2003
Location: Denmark, Viborg
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The easy solution is a small ntc. As this is for a big brutal car sub, 0.5 gram won't make any difference to the unit.
Magura
__________________
Everything is possible....to do the impossible just takes a little while longer. www.class-a-labs.com |
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#7 |
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diyAudio Member
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I didn't see it before, but those procedures can be a little more simple.
Code:
proc nowTemp {VT0 T0 VT1} {
return [expr {[tempRise $VT0 $T0 $VT1] + $T0}]
}
proc tempRise {VT0 T0 VT1} {
return [expr {(1/[thermalCoef $T0])*(($VT1/$VT0)-1)}]
}
__________________
Think out of the box
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#8 |
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diyAudio Member
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I disagree. I say don't modify your driver at all. Just push a little DC bias current through it and monitor the DC voltage and apply a little math.
__________________
Think out of the box
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#9 | |
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diyAudio Member
Join Date: Nov 2005
Location: PA
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Quote:
Maybe you could sense average current and voltage in the power amplifier and apply some processing to that to find changes in DCR. |
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#10 |
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diyAudio Member
Join Date: Oct 2003
Location: Denmark, Viborg
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He forgot to tell you the rest of the story. He is to replace the VC.
Magura
__________________
Everything is possible....to do the impossible just takes a little while longer. www.class-a-labs.com |
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