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Old 30th December 2006, 02:00 PM   #1
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Default Calculation

Hi! I want do to know the power of my amplifier, knowing that the tension is of 25v+25v and RL is 8 ohms.?


hola, quería saber como hago para calcular la potencia de mi amplificador, sabiendo que la tensión es de 25v+25v. y la carga es de 8 ohms?

It is for this amplifier:
Es para este amplificador:
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Old 30th December 2006, 04:01 PM   #2
edl is offline edl  Hungary
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Hi,

If +/-25V is loaded voltage, then the output power is about 30W RMS on 8 ohm.
If 25V is the idle voltage, then it produces about 20W RMS.

Regards,

On the margin for that power I would choose something more elegant, maybe an integrated power amplifier.
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Old 30th December 2006, 04:03 PM   #3
edl is offline edl  Hungary
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At "integrated power amplifier" I mean chip amplifier.
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Old 30th December 2006, 04:06 PM   #4
lineup is offline lineup  Sweden
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Default Re: Calculation

Quote:
Originally posted by aguantesoda
Hi!
I want do to know the power of my amplifier,
knowing that the
Voltage is of 25v+25v and
RL is 8 ohms ?

hola,
quería saber como hago para calcular la potencia de mi amplificador,
sabiendo que la tensión es de 25v+25v.
y la carga es de 8 ohms?

It is for this amplifier:
Es para este amplificador:
For +/-22 Volt peak Max Output ( -3V drop for transistors, and also power supply transformer drop )
FORMULA: P (WATT rms) = ( UxU ) / ( 2xRL )
Watt RMS = 22x22 / 2x8
Watt RMS = 484 / 16

Resultade: 30.25 Watt RMS into 8 Ohm
Answer you get MAX ~30 Watt power / 8 Ohm

(And maybe 40-50 Watt into 4 Ohm speakers )
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Old 30th December 2006, 10:58 PM   #5
edl is offline edl  Hungary
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As I wrote too.
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Old 31st December 2006, 10:02 PM   #6
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Very good! thanks
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