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#1 |
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diyAudio Member
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Hi! I want do to know the power of my amplifier, knowing that the tension is of 25v+25v and RL is 8 ohms.?
hola, quería saber como hago para calcular la potencia de mi amplificador, sabiendo que la tensión es de 25v+25v. y la carga es de 8 ohms? It is for this amplifier: Es para este amplificador: |
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#2 |
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diyAudio Member
Join Date: Oct 2004
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Hi,
If +/-25V is loaded voltage, then the output power is about 30W RMS on 8 ohm. If 25V is the idle voltage, then it produces about 20W RMS. Regards, On the margin for that power I would choose something more elegant, maybe an integrated power amplifier. |
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#3 |
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diyAudio Member
Join Date: Oct 2004
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At "integrated power amplifier" I mean chip amplifier.
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#4 | |
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diyAudio Member
Join Date: Dec 2005
Location: the north
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Quote:
FORMULA: P (WATT rms) = ( UxU ) / ( 2xRL ) Watt RMS = 22x22 / 2x8 Watt RMS = 484 / 16 Resultade: 30.25 Watt RMS into 8 Ohm Answer you get MAX ~30 Watt power / 8 Ohm (And maybe 40-50 Watt into 4 Ohm speakers )
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#5 |
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diyAudio Member
Join Date: Oct 2004
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As I wrote too.
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#6 |
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diyAudio Member
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Very good! thanks
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