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Old 1st December 2006, 10:11 PM   #1
prorms is offline prorms  United States
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Default Amp Will Not Function

I TRY IT OUTWILL NOT FUCTION
GET LOUD BUZZ NOISE OR HUM WITH SINGAL
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Old 1st December 2006, 10:13 PM   #2
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R8 (47k) is connected wrong.
It should be connected to positive rail or ground, not negative rail.
Adam
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Old 1st December 2006, 10:16 PM   #3
prorms is offline prorms  United States
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I CHANGE IT TYPO MISTAKE
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Old 1st December 2006, 10:23 PM   #4
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is R6 really 100ohm?
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Old 2nd December 2006, 02:11 AM   #5
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Hi
I think that I can help it.
I am sorry if I say a misplacement.
Because the detailed movement voltage is unidentified,
it is an estimate, may be in DC design .
So, I attach sample thinking.
I thik the bias circuit is not move enough
(I thik unmatch two bias circuit movement...)

Sincerely.
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Old 2nd December 2006, 02:44 AM   #6
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Sorry I add some Explanation of a revision@for sample circuit.
if using more low Idring current, the way of the diod is to need
change, As it is this is large idring .
(attach sample)

Sincerely.
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Old 2nd December 2006, 10:21 AM   #7
AndrewT is online now AndrewT  Scotland
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Hi Pr,
the input is still connected to the wrong side of R3. You were told this weeks ago.

The gain is 47000/100 + 1 =471.
The output will be about 100mV *471 = 47.1Vac which has a peak value of about 66.6Vp . This exceeds Vrail by quite a margin.

What does C6 do?

Remove D3 & D4 to de-activate the protection until your debugging is complete.
The values are completely wrong.
Short circuit current is limited to about 6.8A which will overload the output devices.
At low Vce the current is allowed to rise to 24Apk and again this is outside the device capability.
You are missing some resistors from the protection circuit. You were told this weeks ago.
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Old 2nd December 2006, 01:15 PM   #8
prorms is offline prorms  United States
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Default ....

what value would be 47volts peak for r9
what percentage did you use for the peak value??
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Old 2nd December 2006, 01:21 PM   #9
prorms is offline prorms  United States
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i move the input ground to above r3 is 10 ohm value
c6 is the miller cap
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Old 2nd December 2006, 03:18 PM   #10
AndrewT is online now AndrewT  Scotland
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C6 is not Miller cap.
The top one around the VAS is the Miller compensation capacitor.

For a sine wave the peak value is square root of two times the rms value.

i.e. Vpk=sqrt2*Vac

If you don't know that you need to do more reading.
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