need help on my config - Page 2

yeti · 29th November 2002, 06:13 AM

You can try to separate the shield in the RCA jack, then connect the resistor to the ground of the jack and the shield on the other side of the resistor.
This should give you a sufficient impedance in the ground loop.
You may try different values of the resistor if the distortion isn't sufficiently cancelled, but don't take values that are too high, because this will cancel the effect of the shield.

hacknet · 2nd December 2002, 06:22 AM

Quote:

Originally posted by yeti
You can try to separate the shield in the RCA jack, then connect the resistor to the ground of the jack and the shield on the other side of the resistor.
This should give you a sufficient impedance in the ground loop.
You may try different values of the resistor if the distortion isn't sufficiently cancelled, but don't take values that are too high, because this will cancel the effect of the shield.

therefore i connect the ground of the output cable to the ground of the output socket?

yeti · 2nd December 2002, 11:55 AM

yes, via the resistor.

LaMa · 2nd December 2002, 12:02 PM

Quote:

Originally posted by Nelson Pass

Otherwise, I would say forget it. Burn the music to CD's
and play it on a portable player.

Don't forget to invest in good headphones.

hacknet · 2nd December 2002, 03:43 PM

Quote:

Originally posted by LaMa

Don't forget to invest in good headphones.

what brand of headphones are good?

29th November 2002, 06:13 AM	#11
yeti diyAudio Member Join Date: Nov 2001 Location: Ewersbach	Resistor You can try to separate the shield in the RCA jack, then connect the resistor to the ground of the jack and the shield on the other side of the resistor. This should give you a sufficient impedance in the ground loop. You may try different values of the resistor if the distortion isn't sufficiently cancelled, but don't take values that are too high, because this will cancel the effect of the shield.

2nd December 2002, 11:55 AM	#13
yeti diyAudio Member Join Date: Nov 2001 Location: Ewersbach	resistor yes, via the resistor.

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