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#1 |
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Audio Junkie
diyAudio Member
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I found a program that will allow me to calculate the steps for a series attenuator. but it requires i enter a number for the total attenuation.
How much attenuation is required for a typical stepped series volume control? This will be placed between a CD player and a Power amp. |
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#2 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
aim for between -60db and -80db. But if you never listen to quiet music a smaller range may do, -40db to -60db. You can also set the first step at -20db (or even higher) if you have a sensitive system that tends to have a high attenuation during all listening sessions.
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regards Andrew T. |
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#3 |
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Audio Junkie
diyAudio Member
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thanks i will give those numbers a shot.
How would i calculate the total resistance of a standard pot for comparison??? |
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#4 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
it will usually be between 10k and 100k. You would not calculate it. Just measure it if the labeling is illegible.
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regards Andrew T. |
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#5 |
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Audio Junkie
diyAudio Member
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Oh i meesed up, i MEANT to say, how would i measure the total attenuation of a pot for comparison.
Zc |
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#6 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi,
most pots will go down to completely off (-infinitydb). Very few audio taper pots are accurate by the time they get to -60db, the balance starts to wander to and fro as you adjust the attenuator. At -80db they are usually hopeless. It is to improve this balance problem that some use a dual linear pot. Then we are in a different ballpark when we go to stepped attenuator. You can easily achieve +-0.1db and even ten times better with selection, both in balance and absolute terms.
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regards Andrew T. |
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#7 |
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diyAudio Member
Join Date: Dec 2005
Location: Kuala Lumpur
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You need to allow for input level variation, which can be as much as 20dB between an old cassette deck and a CD player, so 40dB is too small
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#8 |
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diyAudio Member
Join Date: Nov 2004
Location: In Belgium at the French border.
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Hello Zero Cool,
the attenuation of the pot is 20 log (Rmeasured / Rpot). Example : the pot is Rpot = 10 Kohm, you measure Rmeasured = 100 ohm at the cursor (between cursor and ground) and so you get 20 log (100 / 10000) = -40 dB Regards rephil |
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