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#3751 | |
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diyAudio Member
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Quote:
Like TANH the transfer function of a long tailed FET pair HAS to be expressed as A + Bx**3 + Cx**5.... because it is a symetric odd function. The coefficients will be a function of Idss, Vp, and Ibias. This IS math and not graphs, the exact coefficients might be interesting or not. I have found that one cannot come up with any magic degeneration or arrangement that flattens the transfer function around zero like a bipolar. It is possible an exact solution requires some esoteric transformation of variables or maybe Volterra techniques. I do know that no one I have run into ever found the exact answer interesting. There is no mystery or magic and no non-idealities are necessary. A long tailed pair of anything creates and i1-i2 function that is symetric and odd.
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Pain is never permanent |
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#3752 | |
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Banned
Join Date: Apr 2003
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Quote:
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#3753 |
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Banned
Join Date: Apr 2003
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I am still not finished, but it looks like the last equation on page 2 below can be squared on both sides, then solved for Idm in terms of Vdm. Does this look right so far?
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#3754 |
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diyAudio Member
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You're on the right track, these days I would use a crutch like Mathcad or Matlab to do explicit symbolic answers. They don't miss those factors of two or the square root of PI.
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Pain is never permanent |
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#3755 |
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The one and only
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Let me guess. The answer is 42.
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#3756 |
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diyAudio Member
Join Date: Jul 2003
Location: berkeley ca
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Nelson, we are doing this for you and me. Stick with the program!
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#3757 | |
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Banned
Join Date: Apr 2003
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Quote:
I'll finish this up tomorrow. I got a new pair of speakers yesterday, so I'm doing a marathon listening session at the moment |
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#3758 | |
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diyAudio Member
Join Date: Apr 2002
Location: Prague, Kitakyushu, Fukuoka
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Quote:
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#3759 |
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diyAudio Member
Join Date: Jul 2003
Location: berkeley ca
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So far, you have said nothing that we do not already know.
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#3760 |
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diyAudio Member
Join Date: Apr 2002
Location: Prague, Kitakyushu, Fukuoka
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I have not expected to say anything new. You were asking about 3rd in a long-tailed pair, and argued with 2nd in a single device.
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