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#1 |
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diyAudio Member
Join Date: Nov 2002
Location: Grenoble, FR
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Hi,
I'm looking for a way to subtract 2 signals, but using an opamp subtracter topology. In fact, without feedback at all. Does anyone have a clue? Thanks
__________________
Just remember: in theory there's no difference between theory and practice. But in practice it usually is quite a bit difference... Bob Pease |
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#2 |
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diyAudio Member
Join Date: Aug 2002
Location: Sofia
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What is your application? Is a transformer an option?
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#3 |
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diyAudio Member
Join Date: Nov 2002
Location: Grenoble, FR
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I's for a subtractive crossiver project.
I'd prefer not to use transformers
__________________
Just remember: in theory there's no difference between theory and practice. But in practice it usually is quite a bit difference... Bob Pease |
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#4 |
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diyAudio Member
Join Date: Jan 2004
Location: manchester
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Would a series crossover be ok?
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#5 |
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diyAudio Member
Join Date: Apr 2004
Location: Gütersloh
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How big are the signals that need to be subtracted ? Linelevel or powersignals ?
Obviously, if you don't want to use any feedback, opamps are not welcome ? A simple diffamp typically effectively subtracts two signals, that's why it is called diff-amp... Or you use an "simple" inverter, and use additive resistors ? Mike |
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#6 |
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diyAudio Member
Join Date: Nov 2002
Location: Grenoble, FR
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It's for line level signals (IOW: active crossover, so no series one)
No feedback, you' right Mike. a discrete open loop inverter (do you mean a common emitter with Rc=Re?) and an adder? Yes, that looks like a solution. I'll check that, thanks. I remember having seen a "1 transistor" subtracter somewhere on this forum, but don't remember where exactly . IIRC it has an input on the base, and the other at the collector (or emitter, don't remember exactly)
__________________
Just remember: in theory there's no difference between theory and practice. But in practice it usually is quite a bit difference... Bob Pease |
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#7 |
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diyAudio Member
Join Date: Sep 2002
Location: Sweden
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You can basically use a single BJT and use the base and emitter as inputs. However, using a diff pair will give a much much more linear solution. If you look at the transfer curve of a diff pair, you see that it is very linear within a certain voltage range and quickly becomes very non linear outside it (well, there is no sharp transition, of course). Emitter degeneration extends the linear region. You can either do the math, or just play with Spice and see what the transfer function looks like for various values of emitter degeneration.
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#8 |
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diyAudio Member
Join Date: Nov 2002
Location: Grenoble, FR
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__________________
Just remember: in theory there's no difference between theory and practice. But in practice it usually is quite a bit difference... Bob Pease |
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