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Equalize a passive bi-amp system
Equalize a passive bi-amp system
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Old 1st September 2005, 02:27 PM   #1
Sony is offline Sony  Europe
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Join Date: Sep 2004
Location: Europe
Question Equalize a passive bi-amp system

What is the most audiophile way to equalize a passive bi-amplification system where the power amplifiers have different gains?

- A Pot before one power amplifier.
- Attenuate the loudspeakers drivers (two resistors)?
- Other way.

Thks & Rgrds
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Old 1st September 2005, 02:54 PM   #2
ilimzn is offline ilimzn  Croatia
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Join Date: Feb 2005
Location: Zagreb
A pot )or fixed divider once the attenuation factor is known and tweaked) is the right way, short of:
1) modifying one of the two amps for less/more gain (hardly practical).
2) Adding a transformer or autoformer on the amp output. Driving a loudspeaker (especially if there is a passive crossover in there) normaly implies that the signal source for the speaker system (i.e. amplifier) has negligible internal impedance. Quite obviously this would not be the case, so at best you would get a lot of heat to lose, and more likely, a signifficantly changed frequency response. Therefore, in order to attenuate at the output you would actually need a transformer or autoformer.
3) With some heavy assumption regarding the actual load that has higher sensitivity, you could also modify the crossover to include the attenuation.

Now, all of the above seem far more of a cost and bother than stringing up two resistors per input channel on the amp that needs attenuation, and hence providing input attenuation. However, you did ask for the 'most audiophile' way, that would probably be something along the lines of 2) above
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