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#1 |
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diyAudio Member
Join Date: Jul 2004
Location: Sweden
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Hey
Say you build a standard solid amp with differential input, voltage stage amplification and a good class AB power output stage that is designen for low impedance speaker. What if you would like to use it to drive a couple of headphones? Can this be done by just adding a voltage divider with two resistors on the output? Or is it done by switching to another gain? Or is the signal taken directly from the preamp? |
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#2 |
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diyAudio Member
Join Date: Jun 2005
Location: San Diego, CA
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ALL the above.....
There is no rule from where you get the signal from, as long as you don't degrade the integrity of the signal in the process....... Looking at various amps with headphone monitor, you will see many methods.. I prefer to use a seperate driver/buffer exclusively for the headphones..and tap off the last driver stage prior to the PA sections... Then you can put in a volume pot or "soft" standy-by for the PA section....this way the amplifier can double as a headphone amp and not blow the walls down at 2:00am Chris |
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#3 |
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diyAudio Member
Join Date: Apr 2004
Location: Norwich, UK
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The most commonly used in domestic gear (probably because it's the cheapest) is the voltage divider attenuator method, as it's just 2/3 resistors.
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#4 |
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diyAudio Member
Join Date: Aug 2004
Location: Behind you
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Resistors is the simplest method, but it results in low damping factor, which may or may not sound alright, depending on the headphones. If your preamp can handle the load then that's what I would use.
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https://mrevil.asvachin.eu/ |
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#5 |
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diyAudio Member
Join Date: Nov 2004
Location: Florida
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Why not just have a seperate amp for the headphones, that is driven by the input signal, and the headphones amp and power amp have their own volume controls.
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#6 |
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diyAudio Member
Join Date: Jul 2004
Location: Sweden
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Thanks for all the replies!
Yeah thats alright that too to have a separate amp for the headphones, or making the preamp strong enough for driving headphones. Thanks alot for the tips, im sure i'll solve it in some way =) |
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