Spice model for LED?

G · 13th September 2002, 05:57 PM

Hello all. I just downloaded a circuit simulator from here:

http://www.newburytech.co.uk/Pages/download.html

I would like to simulate the PSU below but I noticed that there is no spice model for an LED. Does anyone know where I could find one? Yes I have searched using google and have had no luck. I've never used a simulator before. Any advice is appreciated.

artnyos · 13th September 2002, 06:05 PM

I have never found one and I have hundreds of spice models.

I doubt you are going to find very decent models for the regulators either just go build thing. It should be fine.

Art

G · 13th September 2002, 06:22 PM

Thanks ART.

rtirion · 13th September 2002, 08:58 PM

For simulation purpose you could replace the led or a zener by a
voltage source.

Regards

mirlo · 13th September 2002, 11:47 PM

http://csserver.evansville.edu/~rich...Modeling_1.pdf

L Daniel Rosa · 14th September 2002, 03:33 AM

Depending on the color and manufacturer, you may end up with an equation that looks a bit like V= 1.97 + 0.08 log(I) + 20I. Good luck.

13th September 2002, 06:05 PM	#2
artnyos Banned Join Date: Sep 2002 Location: New York	spice model for an LED I have never found one and I have hundreds of spice models. I doubt you are going to find very decent models for the regulators either just go build thing. It should be fine. Art

13th September 2002, 06:22 PM	#3
G diyAudio Member Join Date: Apr 2002 Location: Belleville, IL.	Thanks ART. __________________ Gavin

13th September 2002, 11:47 PM	#5
mirlo diyAudio Member Join Date: Jul 2002 Location: San Diego	This might be of some use ... http://csserver.evansville.edu/~rich...Modeling_1.pdf

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13th September 2002, 08:58 PM	#4
rtirion diyAudio Member Join Date: Nov 2000	For simulation purpose you could replace the led or a zener by a voltage source. Regards

14th September 2002, 03:33 AM	#6
L Daniel Rosa diyAudio Member Join Date: Jun 2002 Location: Bellingham WA	Depending on the color and manufacturer, you may end up with an equation that looks a bit like V= 1.97 + 0.08 log(I) + 20I. Good luck.

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