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#1 |
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diyAudio Member
Join Date: Mar 2004
Location: Ypres,Belgium
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Hi,
Just before I do so I would like to know some opinions about paralelling 2xIRFP240 and 2xIRFP9240. One pair IRFP240/IRFP9240 already works just fine in my amp, but since I have one pair left which I don't intend to use... I'd like to parallel these things. Mainly to see what the effects are. So, IR gives some tips on this... separate source resistors for each HEXFET and a carefully designed PCB-layout should do it? Any more hints,tricks,problems? Thanks, Bart |
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#2 |
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diyAudio Member
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post the circuit...first
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SivanandBalan |
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#3 |
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Did it Himself
diyAudio Member
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Make sure the VAS/driver stage can drive the increased capacitance/charge.
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www.readresearch.co.uk my website for UK diy audio people - designs, PCBs, kits and more |
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#4 |
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diyAudio Member
Join Date: Mar 2004
Location: Ypres,Belgium
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Oké, here it is!
It was the IGBT-amp, but since that amp wasn't stable at all, i started to use IRFP240 and IRFP9240 instead and it is working oké. The reason for parallelling is that I have one pair of hexfets extra and...maby the amp will have better performance when fully driven. I know the driverstage has too be able to handle the capacitances of the HEFFET's...but don't know where to start from... We don't see stuff like that at school, and I'd really like to learn. Oké,now here's the circuit (only the IGBT's are replaced by HEXFET's): it's on this site (picture was too big to post) http://www.arky.ru/audio/shem/igbt/igbt.htm |
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#5 |
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diyAudio Member
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Barre,
I have seen your circuit , there are little adjustments that are to be implemented for paralleling mosfets... Gate resistors value should be raised to 39Ohms and source resistors should be around 0.25ohms 5W value.. except this everything seems perfectly okay.... cheers Kanwar
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It's a fruitless endeavor to try and educate a fool that rejoices in ignorance
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#6 |
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diyAudio Member
Join Date: Mar 2004
Location: Ypres,Belgium
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Oké, thank you. Very kind of you.
...but..any chanse you could tel my how you get those numbers? I like to learn you know. But still, thanks :-) Bart Edit: Oké, I found it here ;-) <<<Here is the formula for the adequate driver bleeder resistor choosing. "RDbleeder<=2*[Rgate/N]" where n is total number of mosfets in parallel.>>> |
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#7 | |
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diyAudio Member
Join Date: Dec 2002
Location: Vienna, Austria
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Quote:
With gatestoppers too high you form kind of lo pass filter. Look at the passlabs section as those fets are used by many pass circuits. Uli
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![]() 'Jazz is not dead, it just smells funny' F.Zappa |
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#8 |
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diyAudio Member
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Hi Barre,
If you use too high values of Gate resistors than there may arise a possiblity of cross-conduction at high frequencies....
__________________
It's a fruitless endeavor to try and educate a fool that rejoices in ignorance
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#9 |
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diyAudio Member
Join Date: Mar 2004
Location: Ypres,Belgium
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Hm...
Oké, i will do some breadboard- testing this summer. See what comer out of that. Right now I have exams, and even though this interests me very much... I guess it's not the best time to experiment with that now Thx again and! Btw, are the IR- AN notes any good? Bart |
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