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Old 10th August 2002, 03:39 PM   #1
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Question Push Pull driver newbie question

I'm only an student, and I have built a few push pull amps, all using BJT output devices with a single ended driver, I just want to learn how the push pull driver works and how to design an amp using this stage. i want it to drive a push pull output stage.

Thanks for everybody !!!
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Old 10th August 2002, 05:32 PM   #2
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Nice to meet another student here!! Welcome to diyaudio.com!

What exactly do you want to know? I've put a schematic below of an amp I've just made. So which part you want us to tell you how it works?

best regards,

HB.
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Old 10th August 2002, 05:42 PM   #3
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I recommend you to take a look at the Leach amp

http://users.ece.gatech.edu:80/~mleach/lowtim/

There you have in many parts a classic design in the subject. Since you are new I gather that you haven't heard me nagging about my own stuff?

Check my monster phono amp and monster headphone amp. They are complex (according to some people) but still classic in many senses.

Se link below.
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Old 10th August 2002, 05:51 PM   #4
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You got what I'm looking for Peranders, i'll take a look and tell you if I gets any doubt!
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Old 10th August 2002, 05:54 PM   #5
tiroth is offline tiroth  United States
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hugobross,

I asked this question in another thread without response...say you wanted to drive this amp with a balanced input...would you have to add a reciever stage, or is there still a way to take the feedback to the input stage?
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Old 10th August 2002, 05:54 PM   #6
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some info for Diogo:

R8 and R9 are there to limit the current through the diodes, they can also be replaced by a current source

the diodes are needed to avoid crossover diistortion, also other devices are common.

Q5 is the voltage amplifier stage (C3 reduces higher frequency oscillations), the gain is equal to R12/R13

Q3 and Q4 is a differential amplifier (R3 and R4 reduces little differences between Q3 and Q4). A differential amplifier only 'allow' different signals to go through. (i.e. if the same signal is applied to the base of Q4 and to the base of Q3 there won't go a signal to the base of Q5). When no signal applied, the diff. amp. is 'in balance' => the current through Q3 (I3) is equal to the current through Q4 (I4). I ~ (12V - 0.6V)/R5 = I3 + I4
I3 = I4 so I3 = I/2. Calculation of R7: R7 = 0.6V(Ube of Q5)/I3.

HB.
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Old 10th August 2002, 05:57 PM   #7
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I think it is very interenting, By taking the signal from the emiter the output devices are "looking" at a low impedance input, isn't it great when we talk about mosfet output devices? Won't we get a better low frequency responce?
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Old 10th August 2002, 06:01 PM   #8
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tiroth,

I've been thinking about the same thing, I think you can do it with the same diff. amp but I'm not sure.

to diogo: sorry I see now you were looking for the push pull driver and not the single driver (sorry, I've read your question too fast)

HB.
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Old 10th August 2002, 06:09 PM   #9
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Ok Hugobross, have you ever built one amplifier with the push pull driver?
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Old 10th August 2002, 06:13 PM   #10
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No, I didn't.
But have a look a previous thread:

i want to build a amp with 1-4 Transistor MAX!! -very simple

there's also a nice driver used, maybe this driver is what you're looking for.

HB.
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