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#1 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi all,
Q1. Is there a relationship between the Hi pass filters in a power amplifier a) the DC block at the input and b) at the DC block (gain =1) on the NFB lower leg? Q2. Should the RC time constants be different by a set amount? Q3. If different which should have the larger time constant? Q4. Can the RC be the same? Q5. Are any other roll off points related to these two filters? hope to hear from you all regards Andrew T. |
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#2 |
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diyAudio Member
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I will try to give it a shot on some of your questions
Q1 to Q4: The input Hi Pass should have a higher freq than the NFB, otherwise you will have a gab not covered by the NFB resulting in unwanted low freq amplification. However many uses DC NFB that solves the filter problems
__________________
Free Schematic and Service Manual downloads www.audio-circuit.dk, Company: www.dupont-audio.com, Joint venture: www.DupontMantra.com |
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#3 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi ACD,
do you mean DC NFB = DC servo? or something else. Please explain. regards Andrew T. |
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#4 |
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diyAudio Member
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By DC NFB I mean no cap in the feedback to Gnd!
In this way, small DC offsets will be corrected by the NFB. DC-servo is a complete other thing
__________________
Free Schematic and Service Manual downloads www.audio-circuit.dk, Company: www.dupont-audio.com, Joint venture: www.DupontMantra.com |
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#5 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Thanks ACD, that's clear now. Feedback frequency = 0Hz and input frequency is much higher, fits with your recommendation.
regards Andrew T. |
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#6 |
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diyAudio Member
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High pass on input at app. 5 to 10 Hz should be ok, depending on what you want from the amp
__________________
Free Schematic and Service Manual downloads www.audio-circuit.dk, Company: www.dupont-audio.com, Joint venture: www.DupontMantra.com |
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#7 |
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diyAudio Member
Join Date: Feb 2001
Location: USA
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Power supply caps and load form a pole, the NFB cap must have its pole higher than this.
The input pole must be higher than the NFB pole. NAD uses small supply caps that would normally force the input pole to be quite high, so they make the input pole a two pole filter with a Q=1 (cute). |
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#8 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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Hi DJK,
how do you turn the PSU/load into a pole? Use V/I to generate the load R? What current(I) do you use for the test condition? max power into nominal load or max current of output stage or idling current? regards Andrew T. |
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#9 |
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diyAudio Member
Join Date: Dec 2003
Location: UK
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Hi djk,
Yes, and these interacting poles can sometimes make bass notes sound completely different as you turn the volume up. I've heard it as a 'pumping' or 'pouf' sound as a bass driver causes phase shift. I have for some time now simulated my circuits by applying zero signal input and moving the signal generator to the power rails. This can show up surprising results below 1kHz, not least illustrating a need for high series input capacitor value, if not DC coupling. Cheers ........ Graham. |
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#10 |
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diyAudio Member
Join Date: Feb 2001
Location: USA
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I figure minimum load impedance seen by the power supply and the total filter capacitance of either the positive or negative supply.
Example Hafler DH220 has a pair of 10,000µF and is driving a stereo 4 ohm load. I use 10,000µF and 2R to calculate the pole of 8hz. |
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