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Old 19th November 2004, 10:33 PM   #1
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Default measuring quiescent current of power amp question

hi, i have dual 0.22 ohm emitter resistors when i measure from both outside legs of resistor, do i divide the voltage reading by 0.22 ohms or 0.44 ohms? getting confused thanks, crippledchicken
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Old 19th November 2004, 11:34 PM   #2
jaycee is offline jaycee  United Kingdom
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If you are measuring over both resistors, ie the resistor legs connected to the transistors NOT the output terminal, then you should be dividing by 0.44
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Old 19th November 2004, 11:57 PM   #3
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hi jaycee, thanks for clearing that up for me. crippledchicken
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