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#1 |
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diyAudio Member
Join Date: May 2002
Location: Lexington, KY
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What about a 'passive' shunt attenuator configuration using an e-pot? They're usually 2-wire control and don't require any active circuitry to be in the signal path.
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#2 |
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diyAudio Member
Join Date: Sep 2006
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To Shunt means to direct it to ground. The e-pot is probably an
exponential potentiometer. There are many types of volume controls. If were connect the + and - of the input on an amp. . .no difference in signal will reach the amp and thus no output. If we slowly increase the resistance between the + and - then some signal will reach the amp and the rest will go back to ground (or short). Finally, if there is and infinite amount of resistance between + and -, then the amp will get all the signal. True. . .the exponential potentiometer is between the + and - and not in the signal path; the shunt is the potentiometer and is parallel to the amplifier. . .thus changes the impedance seen by the preamplifier. If you run the pot down to 5 ohms then the preamp will see just less than 5 ohms. . .not a good situation. . . . You should have at least some resistance in the signal path to prevent the impedance from dropping too low. . . you want your preamp to "see" a reasonable load. It would be like running your power amplifier into a 1 ohm load. . .it won't like it! It will get hot, it might shut down, it might stop working. It just cannot supply enough current. . .it needs a load. Preamps need a minimum load also. Put a 5K in series then the shunt pot. . . if the pot is 0 ohms. . .then the preamp "sees" 5k and the amplifier will be silent since it's input is shorted. . . if the pot were at 1 million ohms. . .then the preamp will see something just under the original amplifer impedance plus the 5K. . . .keeps the preamp loaded. Let me know how it works. Chris |
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