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#1 |
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diyAudio Member
Join Date: Feb 2004
Location: Queensland
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Just a simple one. How do you measure the ripple on the output of a capacitor smooothed PSU? Hopefully the ripple voltage will be in the millivolt range but the rail voltage will usually be several tens of volts. Can you do this with a DMM or do you need a CRO?
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"It was the Spring time of the year when aunt calls to aunt like mastodons across the frozen waste." P.G. Wodehouse. |
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#2 |
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diyAudio Member
Join Date: Feb 2004
Location: Queensland
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I must learn to post on my side of the world when the gurus are at their PC's on the other side.
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"It was the Spring time of the year when aunt calls to aunt like mastodons across the frozen waste." P.G. Wodehouse. |
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#3 |
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diyAudio Member
Join Date: Jun 2003
Location: Planet Earth
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G'day, mate
Whichever way you want. Just make an AC measurement. If you're not certain about the capabilities of your measuring device, put a capacitor of maybe 100uF or something in series, charged to the PSU output voltage. With the fairly high input impedance of your measurement equipment, you'll have no problems measuring the AC ripple fairly accurate. Potential problem is that not all DMM's measure "True RMS", but assume that they're seeing a sine shape AC, which is by no means the case for this type of measurement. this gives a faulty read-out of the signal. Jennice
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I get paid to break stuff. My g/f gets paid to play with children. Life is good. |
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#4 |
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diyAudio Member
Join Date: Dec 2003
Location: Orange County, CA
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You use an oscilloscope with the input coupling set to "AC".
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Dan Fraser |
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#5 | |
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diyAudio Member
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Quote:
if you need a good RMS measuring instrument, consider getting a used HP3403C -- or an analog 3400 -- |
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#6 |
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diyAudio Member
Join Date: Jun 2004
Location: Knoxville
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What ever happened to mathmatics??
If you know how much current the power supply outputs, and you know what the capacitor values are, and the frequency of AC Line with rectifier, 50-60Hz or 100-120Hz(full wave), then you should be able to calculate the ripple voltage. I think it is I(load) / (C * f) but I am not sure. You may want to look up the formula. |
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#7 |
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diyAudio Moderator
Join Date: Jun 2004
Location: Georgetown, On
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Hi jackinnj,
Jennice was refering to "crest factor". The ratio of peak voltage to rms voltage. Any deviation from a sine wave has an amount of crest factor. This can be approximated and corrected for if you really know your meter. BTW, inexpensive meters I have calibrated often don't meet their own published specs, or hold cal. very well. Many fail out of the box! I guess it depends on how accurate you want your readings to be. -Chris |
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#8 |
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diyAudio Member
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One measurement with a scope is worth a thousand equations!
\Jens |
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#9 | |
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diyAudio Member
Join Date: Feb 2002
Location: The Netherlands (Friesland)
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Quote:
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We will pay the price, but we will not count the cost... |
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#10 |
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diyAudio Moderator
Join Date: Jun 2004
Location: Georgetown, On
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Oh yeah! Especially a digital 'scope that will do the math & tell you the answer.
Mark25, I think many meters would just make an answer up. -Chris |
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