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Old 14th April 2004, 09:20 AM   #11
wopo is offline wopo  Austria
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Hello!

Here are 3 photos of my Leachamp:

Click the image to open in full size. Click the image to open in full size. Click the image to open in full size.
Wopo
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Old 14th April 2004, 01:08 PM   #12
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Wow, very impressive, did you guys etch and drill your own boards?
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Old 14th April 2004, 11:19 PM   #13
Tony is offline Tony  Philippines
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Default i used silkscreen method

yes, i used silkscreen, etched and drilled the boards my self, i have three sets stuffed with parts waiting assembly....
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Old 14th April 2004, 11:20 PM   #14
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For sale? =)
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Old 14th April 2004, 11:24 PM   #15
Tony is offline Tony  Philippines
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Default post #8 boards

yes, please send me email, tonyjtec@yahoo.com
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Old 15th April 2004, 01:07 AM   #16
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A message that you sent could not be delivered to one or more of its
recipients. This is a permanent error. The following address(es) failed:

tonyjtec@yahoo.com
SMTP error from remote mailer after end of data:
host mx2.mail.yahoo.com [67.28.114.32]: 554 delivery error:
dd Sorry your message to tonyjtec@yahoo.com cannot be delivered. This account has been disabled or discontinued [#102]. - mta120.mail.dcn.yahoo.com
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Old 15th April 2004, 02:25 AM   #17
Tony is offline Tony  Philippines
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ooopss, sorry, got my e-mails mixed up, it should be tonyjtec@hotmail.com or tonytecson@yahoo.com.....
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Old 15th April 2004, 08:55 AM   #18
dulel is offline dulel  Yugoslavia
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Q8 and Q9 in Leachamp do not have any function. Current in VAS is already limited by the maximum voltage that can occur on VAS transistor bases. This voltage is equal R11 or R12 multiplied by maximum tail current. In this case maximum VAS base voltage is 1.2k * 40V/12k = 4V. Vas current is limited to 3.3V/390ohm = 8.5 mA which is well below current nedded for Q8 an Q9 conduction (20mA).

This kind of current protection is effective if current mirror is used in input stage, and therefore maximum VAS transistor base voltage can't be determined.

regards, Dule
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Old 26th April 2004, 02:06 AM   #19
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Quote:
Originally posted by dulel
Q8 and Q9 in Leachamp do not have any function. Current in VAS is already limited by the maximum voltage that can occur on VAS transistor bases. This voltage is equal R11 or R12 multiplied by maximum tail current. In this case maximum VAS base voltage is 1.2k * 40V/12k = 4V. Vas current is limited to 3.3V/390ohm = 8.5 mA which is well below current nedded for Q8 an Q9 conduction (20mA).

This kind of current protection is effective if current mirror is used in input stage, and therefore maximum VAS transistor base voltage can't be determined.

regards, Dule
You noticed that too, hun? I wrote Dr. Leach about this 3 years ago, and he replied back explaining how the current limit function worked, but missed the point. He must get tons of email, so I was glad to hear back, but he never took it seriously. I suspect this circuit has been there for decades and he changed something else to make it redundant, not realizing it.

You can leave out these VAS current limiters if you like. If the main output protection kicks in, the VAS current does get diverted to the output, so a limit is advisable, but like you I can't see what good this does because of the values selected.
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