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#2701 |
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diyAudio Member
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Well, the issue is the topology. It uses a phase splitter to drive the output devices. The phase splitter has to work in Class A - because if you let this device turn off then it no longer controls the current flow. And it must control the current flow in at least one of the output transistors even in Class B. In order for the lower output device to turn off (in Class B) you have to let the phase splitter device turn off. At least this is how I see it. So I don't think you can do it - the distortion will be awful.
If you want to have an amp that can operate in Class A and switch out into Class B when it runs out of bias current you need a different topology. A suitable topology would be the more common complimentary output devices so that it's the output devices that do the 'phase splitting' - rather like the JLH Class B amplifier (described on this site: http://sound.au.com/tcaas/jlhab.htm) I think both the simple Class A amp and his simple Class B amp would sound very nice. But do you need the higher power - you may find with the right speakers that the Class A amp is loud enough.
__________________
"The test of the machine is the satisfaction it gives you. There isn't any other test. If the machine produces tranquility it's right. If it disturbs you it's wrong until either the machine or your mind is changed." Robert M Pirsig. Last edited by Bigun; 18th March 2013 at 11:34 PM. |
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#2702 | |
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diyAudio Member
Join Date: Apr 2010
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Quote:
I was going to go with Class A but thought of trying it running as old tube amps were, biased about 60-70% and then switch to Class A to see if I could hear any difference. Just for curiosity sake. This may take a bit more thought. |
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#2703 | |
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diyAudio Member
Join Date: Nov 2007
Location: Dallas
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Quote:
shaping drive currents in a non-linear way that would produce AB output currents. Non-linearity of the default 2n3055 output transistor bends the wrong way for natural AB with reduced idle current. Indeed idle current of the JLH output totem is far MORE than the peak output current and in wasteful excess of linear class A! If you wish to reduce idle currents in AB fashion, you'll have to sabotage the ideal constant drive current source that can be steered only two ways. You'll either need to restrict excess drive current during the AB crossing, or shunt it somewhere else than output bases during the crossing. I've found an easy way to shape the drive currents for square law AB that can be grafted onto an existing JLH circuit. But my AB solution with Schottkys for current sensing sometimes oscillates. Not recommending till I figure why it does that. Fine if you just want to use current sense resistors (instead of Schottkys) to shape for linear class A behavior. Search the forum for SRJLH, but don't built the AB option unless you have some deep insight how to fix the oscillations. Last edited by kenpeter; 19th March 2013 at 12:36 AM. |
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#2704 |
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diyAudio Member
Join Date: Apr 2010
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Might just be easier to get a Class AB amp and bias it for Class A?
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#2705 | ||
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diyAudio Moderator
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Here is the original JLH running as low as 500ma bias. Lets be clear on the question. Running it at 1 amp as you wish doesn't really fit the accepted definition of Class AB. To me a class AB amp is one running at the correct current for the output stage topology chosen.
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------------------------------------------------------- A simulation free zone. Design it, build it, test it. |
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#2706 | |
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diyAudio Member
Join Date: Apr 2010
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Quote:
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#2707 | |
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diyAudio Moderator
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Quote:
__________________
------------------------------------------------------- A simulation free zone. Design it, build it, test it. |
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#2708 |
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diyAudio Member
Join Date: Apr 2010
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#2709 | |
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diyAudio Member
Join Date: Jan 2008
Location: Italy
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Quote:
Power is power, nothing else. We are speaking of PowerRMS: [W RMS] = [A RMS] * [V RMS] When i misure Ibias with my digital multimeter I measure it by [A RMS] (Ampere RMS), not Apk, nor App of course. This is because multimeter makes only measurements of Voltage RMS, even if it is measuring Ampere; in fact it then divide Voltage measurement by a shunt resistor, to obtain correct value of I, expressed in [A RMS]. So if I measure Ibias = 1.75A RMS and I connect a 4ohm loudspeaker, then the output power is: (1.75^2)*4 = 12.25W RMS. In this calculation I can ignore the voltage value beacause I know it is sure enough. In fact: 1.75A*4ohm = 6.125V Vcc(min) = 2*(6.125V+0.7V) = 13.65V (<<48V). So if I want an output power of 12.25W on a load of 4ohm I have to bias my JLH@ 1.75A rms and 13.65V rms. But it is not so simple. If I want to drive 2ohm too @12.25W? sqrt(12.25Wrms/2ohm) = 2.5A rms circa. {It's different from sqrt(12.25Wrms/4ohm) = 1.75A rms.} So: 2*(2.5Arms*2ohm+0.7V) = 11.4V rms (but I've got 13.65V, so it's ok). I have to increase Ibias from 1.75A to 2.5A. 8ohm? 1.75Arms*8ohm = 14Vrms. 14Vrms*1.75Arms = 24.5W rms. So I need a Vcc = 2*(0.7Vrms+14Vrms) = 29.4V rms. (13.65V is no more ok, and I have to increase a lot the PSU). At the end of the story a correct couple of values to drive whatever @12.25W rms (min) is: 2.5Arms @30Vrms [12.25W rms A Class @2/4 ohm, 24.5W rms A Class @8 ohm]. I agree with you of course when you say 'There is no advantage in increasing Vdc of the PSU AND reducing the speaker impedance from 8ohms to 4ohms'. I only said I polarized my JLH @48V when someone asked if anybody out there (cit.) did, not said it's a good choice. Last edited by iperv; 20th March 2013 at 01:30 AM. |
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#2710 |
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diyAudio Member
Join Date: Jul 2004
Location: Scottish Borders
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No.
Ibias is a DC current. |
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