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#101 |
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diyAudio Member
Join Date: Sep 2001
Location: Melbourne, Australia
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Because there is no open loop voltage gain, and therefore no feedback factor?
Hugh |
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#102 | |
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diyAudio Member
Join Date: Sep 2002
Location: Sacramento, CA
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se |
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#103 |
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diyAudio Member
Join Date: Sep 2001
Location: Melbourne, Australia
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OLG is fundamental to calculating feedback factor.
The ratio of OLG to CLG is, as I'm sure you realize, the feedback factor. If you wish to prove me wrong, go right ahead. It's not important. In truth, the question is, as someone put it, roaringly funny. Hugh |
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#104 | ||||
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diyAudio Member
Join Date: Sep 2002
Location: Sacramento, CA
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If one directly feeds the opamp's output into its inverting input, creating a unity gain buffer, does that loop not contain the open loop gain of the opamp? In other words, if you follow the loop around, the opamp's open loop gain is part of that loop. You have the input, the summing node, then the opamp's open loop gain, the output which goes into the feedback network which is then fed to the summing node. Point I was getting at was that the opamp's open loop gain doesn't just disappear. If it did, then feedback wouldn't be able to do the things that it does. So now let me get more to the point. Let's say you've got an unknown opamp with an unknown open loop gain configured as a unity gain buffer. You can determine that it's gain is 1. But you're not going to know what the open loop gain is and subsequently the feedback factor. So what do you do? You configure it as an open loop amplifier and measure its open loop gain. If it's open loop gain is 100,000, you know that the feedback factor is also 100,000 and you've got 100dB of feedback. Why is a transistor fundamentally any different? If a transistor configured as a common-emitter amplifier with say 100 ohms for RC gives you a gain of say 100, is not the same transistor configured as a common-collector amplifier with 100 ohms for RE an amplifier which has a feedback factor of 100 and 40dB of feedback? I don't see any fundamental difference here. se |
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#105 |
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diyAudio Member
Join Date: Sep 2003
Location: WA
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If an amplifier circuit has three stages: 1st stage gain = 15, 2nd stage gain of 75, and 3rd stage gain of 1, it has a open loop gain of 1125 (~67db). Feedback does not change the gain of each of the stages. The signal from the inputs is smaller with more feedback. The more feedback, the smaller the difference signal.
This is kind of interesting. So, with an op-amp with an OLG of 10,000. Configure it as a buffer. Apply 2VAC. Output is 2VAC. However, the difference signal at input of the first stage is 200uVAC. If the CLG is 10, then, of course, the signal is 2mVAC. I imagine that something similar happens with single/compound active device circuits (meaning the gain of the devices remains the same OL v CL). JF |
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#106 |
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diyAudio Member
Join Date: Sep 2003
Location: WA
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I found out that my input stage is idling at 2mA (which I'm matching JFETs to) and has a maximum variation of 40uA with feedback. Output of the first stage is 3Vdc and maximum of 50mV ac. Open loop, of course, the variation is much higher.
JF |
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#107 |
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diyAudio Member
Join Date: Jan 2004
Location: Koskenkorva Land
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SE,
were you stunned ower my little "trick" in Post #95, or perhaps you didn't discover it...? Do you think there are "feedback" in diodes too as well as with CC's!?? Cheers!
__________________
"If transistors are blueberries and FETs are strawberries, then tubes must be.. pears" Michael 29th January 2010 |
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#108 | |
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diyAudio Member
Join Date: Sep 2002
Location: Sacramento, CA
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#109 |
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The one and only
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You guys are very entertaining (in a perverse way) but you
really need to look at the question from another angle. An example would be: Ask the question, "What is different about each transistor's experience in the two configurations?" |
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#110 | |
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diyAudio Member
Join Date: Sep 2002
Location: Sacramento, CA
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Quote:
se |
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