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#31 |
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diyAudio Member
Join Date: Sep 2002
Location: Sweden
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Andy_c,
how did you get .fourier to work in LTSpice? It is not available in the GUI, and explicitly adding it as a command in the schematic didn't do anything. It is not long ago since I upgraded my version, but maybe they have just included it?? BTW, I tried to rerun with a larger time step and switch off compression. That made quite an improvement. It didn't give quite the same figures, but close. It must obvioulsy be a lossy compression. I'll make some more experiments with the other suggestions. My PC shouldn't be that much slower than yours, so it seems worthwhile experiimenting with. |
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#32 | |
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diyAudio Member
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Quote:
This command displays the output of the SPICE engine itself, as would running a command line version would do. Also usefull when running .op => gives table of active devices parameters at operating point. Regards, Peter Jacobi
__________________
-- YMMV |
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#33 |
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diyAudio Member
Join Date: Sep 2002
Location: Sweden
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Sounds almost a bit Microsoftish that one should have to view the
errorlog to get ordinary runtime output. Edit: Yes, I just tried and it worked fine. BTW, I just tried to run with a rather large time step, but without compression and suddenly it made a lot of difference to use windowing in the FFT. I got almost the same result as before using a 1us time step and a Hann window. Previously windowing has made little of no difference, That compression must be terribly lossy. That makes an old question much more relevant, how to know which window to use? Empirical tries only, or is there some rule of thumb on this? |
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#34 |
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Banned
Join Date: Apr 2003
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Kind of like exiting via the "start" button?
If you still can't duplicate my results I can post my .asc file if you'd like. |
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#35 | ||
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diyAudio Member
Join Date: Sep 2002
Location: Sweden
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Quote:
Quote:
the fourier results that way. Too late do any more simulations right now, but thanks for the help. I would never have have got the idea of looking in the error log, especially since LTSPice gives me the impression of being written by someone used to real OS's. |
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#36 | |
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diyAudio Member
Join Date: Jun 2002
Location: Serbia
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Quote:
Pedja |
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#37 |
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diyAudio Member
Join Date: Sep 2001
Location: Melbourne, Australia
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Christer & Guys,
This is very interesting. Can you pretty much specify the input impedance by simply setting the bias resistor? Could you achieve a 200K Zin, for example? Christer, you say Class A. I presume by this you mean that none of the devices ever switches off; certainly the idle current is much lower than the 45mA you say it will swing into a load with 5Vpp. Do you see application for the output stage of a power amplifier? For myself, having tried CFPs some time ago, I found that instability precluded this, but of course high idle Class A should be fine. Cheers, Hugh |
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#38 | |||
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diyAudio Member
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Hi Aksa, All,
Quote:
Quote:
Quote:
But the instability wouldn't go away because of the nice looking topology alone. I've got a simulated amplifier stable with a outbuf buffer like that one: http://www.linearaudio.de/scratch/DARL-BUFFER.pdf http://www.linearaudio.de/scratch/DARL-BUFFER.asc Note that the boosters became darlingtons, to have fast, high-beta BJTs in the diamond itself, so the whole would qualify for 'output triples'. Also complications arose to have some gain in the buffer, for the goal of getting the highest possible voltage swing. Regards, Peter Jacobi
__________________
-- YMMV |
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#39 | ||
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diyAudio Member
Join Date: Sep 2002
Location: Sweden
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Quote:
in parallel with beta*Re for the output stage (assuming the follower version). This shuld be the limiting factor, so very high input Z seems somewhat diffiult to achieve for low Re values. I might be wrong though, considering the late hour. Quote:
I got. I think I posted them earlier, though. For the third question I am not so sure it would work without some temp. comp. for the output bias, but maybe the buffer actually does this withouth explicit temp. comp. I will have to think more about that. |
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#40 | |
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diyAudio Member
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Quote:
For the #3 circuit, most of the output conductance is hidden from the diamond by the booster BJTs, which take almost all of the current swing. So the diamond's output stage is effectively also driving current sources. (Of value Vbe(Q6)/R10 = about 7mA). Count this on the 'pro' side for using boosters. Without them, we would indeed be at beta1*beta2*Rload. Regards, Peter Jacobi
__________________
-- YMMV |
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